PHP exec() 不在输出中返回错误消息
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PHP exec() not returning error message in output
提问by Goran
I am trying to get certain output for svn command in XML format. Output is ok when I type valid parameters. However, when I type in wrong password, output does not show error message. This is the PHP code:
我正在尝试以 XML 格式获取 svn 命令的某些输出。当我输入有效参数时，输出正常。但是，当我输入错误的密码时，输出不显示错误消息。这是PHP代码：
exec('/usr/bin/svn --username something --password something --non-interactive log -r HEAD --xml --verbose http://a51.unfuddle.com/svn/a51_activecollab/', $output);
Here is output I get in the terminal:
这是我在终端中得到的输出：
<?xml version="1.0"?>
<log>
svn: OPTIONS of 'http://a51.unfuddle.com/svn/a51_activecollab': authorization failed: Could not authenticate to server: rejected Basic challenge (http://a51.unfuddle.com)
And here is the output I get from the $output variable with var_dump:
这是我从带有 var_dump 的 $output 变量得到的输出：
array(2) {
[0]=>
string(21) "<?xml version="1.0"?>"
[1]=>
string(5) "<log>"
}
As you can see the $output variable does not return third line of output, where terminal does. Please help me to get the same output as I get in terminal (I even tried with shell_exec() or system() methods but they return the same output as exec()) How do I get full output? Thank you in advance!
如您所见， $output 变量不会返回第三行输出，而终端会返回。请帮助我获得与终端相同的输出（我什至尝试使用 shell_exec() 或 system() 方法，但它们返回与 exec() 相同的输出） 如何获得完整输出？先感谢您！
回答by racetrack
You need to capture the stderrtoo.
你也需要捕捉stderr。
Redirecting stderrto stdoutshould do the trick. Append 2>&1to the end of your command.
重定向stderr到stdout应该可以解决问题。附加2>&1到命令的末尾。
e.g.
例如
exec("/usr/bin/svn --username something --password something --non-interactive log -r HEAD --xml --verbose http://a51.unfuddle.com/svn/a51_activecollab/ 2>&1", $output);
回答by Cedric
That is probably not the solution, just a bad suggestion : have you tried to add an extra echo in the command:
这可能不是解决方案，只是一个不好的建议：您是否尝试在命令中添加额外的回声：
exec('/usr/bin/svn --username something --password something --non-interactive log -r HEAD --xml --verbose http://a51.unfuddle.com/svn/a51_activecollab/;**echo ""**', $output);
And the other way to solve that is as already mentionned : if you don't have the last line in the $output, it is in the returned value of the exec() function anyway. You'd have then
解决这个问题的另一种方法是已经提到的：如果 $output 中没有最后一行，无论如何它都在 exec() 函数的返回值中。那时你会
$totalOutput = push($msg,$output);
with
和
$msg = exec('/usr/bin/svn --username something --password something --non-interactive log -r HEAD --xml --verbose http://a51.unfuddle.com/svn/a51_activecollab/', $output);
回答by ant
You need to define a variable in which to store the message
您需要定义一个变量来存储消息
$msg = exec('/usr/bin/svn --username something --password something --non-interactive log -r HEAD --xml --verbose http://a51.unfuddle.com/svn/a51_activecollab/');
$msg = exec('/usr/bin/svn --username something --password something --non-interactive log -r HEAD --xml --verbose http://a51.unfuddle.com/svn/a51_activecollab/');
