Java 如何在 Kotlin 中将字符串拆分为数组？
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How could I split a String into an array in Kotlin?
提问by Michael F.
I need to split a String read in from a file into an array of values. I want to split the String at the commas, so for example, if the String read:
我需要将从文件中读取的字符串拆分为值数组。我想在逗号处拆分字符串，例如，如果字符串读取：
"name, 2012, 2017"
The values in the array would be:
数组中的值将是：
- array index 0 - name
- array index 1 - 2012
- array index 2 - 2017
- 数组索引 0 - 名称
- 数组索引 1 - 2012
- 数组索引 2 - 2017
I found this example in Java:
我在 Java 中找到了这个例子：
String[] stringArray = string.split(",");
How I could do it in Kotlin?
我怎么能在 Kotlin 中做到这一点？
采纳答案by JK Ly
val strs = "name, 2012, 2017".split(",").toTypedArray()
回答by Hamed Jaliliani
If we have a string of values that splited by any character like ",":
如果我们有一串值被任何像“,”这样的字符分割：
val values = "Name1 ,Name2, Name3" // Read List from somewhere
val lstValues: List<String> = values.split(",").map { it -> it.trim() }
lstValues.forEach { it ->
Log.i("Values", "value=$it")
//Do Something
}
It's better to use trim() to delete spaces around strings if exist. Consider that if have a "," at the end of string it makes one null item, so can check it with this code before split :
如果存在，最好使用 trim() 删除字符串周围的空格。考虑到如果在字符串末尾有一个“,”，它会生成一个空项，因此可以在 split 之前使用以下代码进行检查：
if ( values.endsWith(",") )
values = values.substring(0, values.length - 1)
if you want to convert list to Array ,use this code:
如果要将 list 转换为 Array ，请使用以下代码：
var arr = lstValues.toTypedArray()
arr.forEach { Log.i("ArrayItem", " Array item=" + it ) }
回答by Thiago Silva
Simple as it is:
很简单：
val string: String = "leo_Ana_John"
val yourArray: List<String> = string.split("_")
you get: yourArray[0] == leo, yourArray[1] == Ana, yourArray[2]==John
你得到： yourArray[0] == leo, yourArray[1] == Ana, yourArray[2]==John
回答by Manikandan
Split a string using inbuilt split method then using method extensions isNum() to return numeric or not.
使用内置的拆分方法拆分字符串，然后使用方法扩展 isNum() 返回数字或不返回。
fun String.isNum(): Boolean{
var num:Int? = this.trim().toIntOrNull()
return if (num != null) true else false
}
for (x in "name, 2012, 2017".split(",")) {
println(x.isNum())
}
