java.lang.String 不能转换为 org.json.simple.JSONObject simple-json
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java.lang.String cannot be cast to org.json.simple.JSONObject simple-json
提问by Roshan Wijesena
I am getting strange problem while trying to parse a simple json using simple-json by google.
我在尝试使用 Google 的 simple-json 解析一个简单的 json 时遇到了奇怪的问题。
Here is my code which is not working:
这是我的代码不起作用：
String s = args[0].toString();
JSONObject json = (JSONObject)new JSONParser().parse(s);
When I execute, it will give me the exception java.lang.String cannot be cast to org.json.simple.JSONObject
当我执行时，它会给我异常 java.lang.String cannot be cast to org.json.simple.JSONObject
But when I hard code json directly like below its working fine. Wat could be the reason?
但是当我直接像下面那样硬编码 json 时，它的工作正常。Wat可能是原因？
JSONObject json = (JSONObject)new JSONParser().parse("{\"application\":\"admin\",\"keytype\":\"PRODUCTION\",\"callbackUrl\":\"qwerewqr;ewqrwerq;qwerqwerq\",\"authorizedDomains\":\"ALL\",\"validityTime\":\"3600000\",\"retryAfterFailure\":true}");
UPDATE
更新
When I print s, it will give me the output below:
当我打印 s 时，它会给我以下输出：
"{\"application\":\"admin\",\"keytype\":\"PRODUCTION\",\"callbackUrl\":\"qwerewqr;ewqrwerq;qwerqwerq\",\"authorizedDomains\":\"ALL\",\"validityTime\":\"3600000\",\"retryAfterFailure\":true}"
采纳答案by Ankur Singhal
I ran this through eclipse by providing argumentsin run configuration.
我通过提供运行这个月食通过arguments在run configuration。
public static void main(String[] args) {
String s = args[0].toString();
System.out.println("=>" + s);
try {
JSONObject json = (JSONObject) new JSONParser().parse(s);
System.out.println(json);
} catch (ParseException e) {
e.printStackTrace();
}
}
Output
输出
=>{"application":"admin","keytype":"PRODUCTION","callbackUrl":"qwerewqr;ewqrwerq;qwerqwerq","authorizedDomains":"ALL","validityTime":"3600000","retryAfterFailure":true}
{"validityTime":"3600000","callbackUrl":"qwerewqr;ewqrwerq;qwerqwerq","application":"admin","retryAfterFailure":true,"authorizedDomains":"ALL","keytype":"PRODUCTION"}
回答by Shailendra
Try this
尝试这个
package com.test;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;
public class JSONTest {
public static void main(String[] args) {
String s = args[0];
try {
JSONObject json = (JSONObject) new JSONParser().parse(s);
System.out.println(json);
} catch (ParseException e) {
e.printStackTrace();
}
}
Then on command line
然后在命令行
java -classpath ".;json-simple-1.1.1.jar" com.test.JSONTest {\"application\":\"admin\",\"keytype\":\"PRODUCTION\",\"callbackUrl\":\"qwerewqr;ewqrwerq;qwerqwerq\",\"authorizedDomains\":\"ALL\",\"validityTime\":\"3600000\",\"retryAfterFailure\":true}
The out put is
输出是
{"validityTime":"3600000","callbackUrl":"qwerewqr;ewqrwerq;qwerqwerq","application":"admin","retryAfterFailure":true,"authorizedDomains":"ALL","keytype":"PRODUCTION"}
