Java字符串用&替换'&' 但不是 & 到 &

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时间:2020-08-11 00:39:24  来源:igfitidea点击:

Java String Replace '&' with & but not & to &

javaregexstringreplaceampersand

提问by sribasu

I have a large String in which I have & characters used available in following patterns -

我有一个大字符串,其中有 & 字符可用于以下模式 -

A&B
A & B
A& B
A &B
A&B
A & B
A& B
A &B

I want to replace all the occurrences of & character to &While replacing this, I also need to make sure that I do not mistakenly convert an &to &. How do I do that in a performance savvy way? Do I use regular expression? If yes, please can you help me to pickup the right regular expression to do the above?

我想将所有出现的 & 字符&替换为在替换它时,我还需要确保我没有错误地将 an 转换&&. 我如何以精通性能的方式做到这一点?我使用正则表达式吗?如果是,请您帮我选择正确的正则表达式来执行上述操作吗?

I've tried following so far with no joy:

到目前为止,我一直没有高兴地尝试以下操作:

data = data.replace(" & ", "&"); // doesn't replace all &
data = data.replace("&", "&");   // replaces all &, so & becomes &

采纳答案by khampson

You can use a regular expression with a negative lookahead.

您可以使用带有否定前瞻的正则表达式。

The regex string would be &(?!amp;).

正则表达式字符串将是&(?!amp;).

Using replaceAll, you would get:

使用replaceAll,你会得到:

A&B
A & B
A& B
A &B
A&B
A & B
A& B
A &B

So the code for a single string strwould be:

所以单个字符串的代码str将是:

str.replaceAll("&(?!amp;)", "&");

回答by gleba

You can try this, it should work:

你可以试试这个,它应该可以工作:

data = data.replaceAll("&","&").replaceAll("&","&");

That way you first replace all &with &so all you'll have is &, and then, you replace all of them with &.

这样,您首先将所有内容替换为&&因此您将拥有的只是&,然后,您将所有内容替换为&