windows 为什么 GetCurrentProcess 返回 -1？
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Why does GetCurrentProcess return -1?
提问by Kmd
In this small program, why does GetCurrentProcess()return -1?
在这个小程序中，为什么GetCurrentProcess()返回-1？
int _tmain(int argc, _TCHAR* argv[]) {
HANDLE h = GetCurrentProcess(); // ret -1
printf("0x%x\n",(DWORD)h);
return 0;
}
What's wrong?
怎么了？
In Kernel32.GetCurrentProcessI see this:
在Kernel32.GetCurrentProcess我看到这个：
OR EAX,FFFFFFFF ; EAX - ?
RETN
回答by Skizz
That is correct, see this API reference for GetCurrentProcess.
没错，请参阅GetCurrentProcess 的此 API 参考。
The
GetCurrentProcessfunction retrieves a pseudo-handle for the current process, which is currently defined as(HANDLE)-1. However, because you should not assume that the value will never change, theGetCurrentProcessfunction is provided as an alternative to hard-coding the constant into your code.
该
GetCurrentProcess函数检索当前进程的伪句柄，当前定义为(HANDLE)-1。但是，因为您不应该假设该值永远不会改变，所以GetCurrentProcess提供该函数作为将常量硬编码到您的代码中的替代方法。
回答by user703016
-1is the pseudo-handle that represents the current process. It's normal.
-1是代表当前进程的伪句柄。这是正常的。
回答by vrajs5
There is nothing wrong with -1 value. It will indicate current process handle. You can refer remark section in this msdn page
-1 值没有任何问题。它将指示当前进程句柄。您可以参考此 msdn 页面中的备注部分
