Java org.hibernate.exception.GenericJDBCException：无法在休眠中执行语句
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org.hibernate.exception.GenericJDBCException: could not execute statement in hibernate
提问by Dipesh Raichana
I am trying to use embeddable annotation to store different values in one object to be persisted in one table.
我正在尝试使用可嵌入的注释将不同的值存储在一个对象中，以便在一个表中持久化。
I have two classes: userDetails:
我有两个类：userDetails：
package org.hibernet.src;
@Entity
@Table (name="UserDetails")
public class userDetails {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int userId;
@Temporal(TemporalType.DATE)
private Date dob;
public Date getDob() {
return dob;
}
public void setDob(Date dob) {
this.dob = dob;
}
private String userName;
@Embedded
private Address address;
public Address getAddress() {
return address;
}
public void setAddress(Address address) {
this.address = address;
}
public int getUserId() {
return userId;
}
public void setUserId(int userId) {
this.userId = userId;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
}
Address class which is embeddable class:
@Embeddable public class Address { @Column(nullable=true) private String street; @Column(nullable=true) private String city; @Column(nullable=true) private String state; public String getStreet() { return street; } public void setStreet(String street) { this.street = street; } public String getCity() { return city; } public void setCity(String city) { this.city = city; } public String getState() { return state; } public void setState(String state) { this.state = state; }} this is my main class:
public static void main(String[] args) { userDetails user = new userDetails(); Address add = new Address(); user.setUserName("Dipesh"); user.setDob(new Time(0)); add.setCity("vadodara"); add.setState("gujarat"); add.setStreet("raopura"); SessionFactory sessionfactory = new Configuration().configure().buildSessionFactory(); Session session = sessionfactory.openSession(); session.beginTransaction(); session.save(user); session.save(add); /*user = (userDetails)session.get(userDetails.class, 6);*/ session.getTransaction().commit(); session.close();}
可嵌入类的地址类：
@Embeddable public class Address { @Column(nullable=true) private String street; @Column(nullable=true) private String city; @Column(nullable=true) private String state; public String getStreet() { return street; } public void setStreet(String street) { this.street = street; } public String getCity() { return city; } public void setCity(String city) { this.city = city; } public String getState() { return state; } public void setState(String state) { this.state = state; }这是我的主要课程：
public static void main(String[] args) { userDetails user = new userDetails(); Address add = new Address(); user.setUserName("Dipesh"); user.setDob(new Time(0)); add.setCity("vadodara"); add.setState("gujarat"); add.setStreet("raopura"); SessionFactory sessionfactory = new Configuration().configure().buildSessionFactory(); Session session = sessionfactory.openSession(); session.beginTransaction(); session.save(user); session.save(add); /*user = (userDetails)session.get(userDetails.class, 6);*/ session.getTransaction().commit(); session.close();}
I was trying to store the data but it was showing:
我试图存储数据，但它显示：
ERROR: Field 'pincode' doesn't have a default value
Exception in thread "main" org.hibernate.exception.GenericJDBCException:
could not execute statement
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:54)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:211)
at org.hibernate.id.IdentityGenerator$GetGeneratedKeysDelegate.executeAndExtract(IdentityGenerator.java:96)
at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:58)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3032)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3558)
at org.hibernate.action.internal.EntityIdentityInsertAction.execute(EntityIdentityInsertAction.java:98)
at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:490)
at org.hibernate.engine.spi.ActionQueue.addResolvedEntityInsertAction(ActionQueue.java:195)
at org.hibernate.engine.spi.ActionQueue.addInsertAction(ActionQueue.java:179)
at org.hibernate.engine.spi.ActionQueue.addAction(ActionQueue.java:214)
at org.hibernate.event.internal.AbstractSaveEventListener.addInsertAction(AbstractSaveEventListener.java:324)
at org.hibernate.event.internal.AbstractSaveEventListener.performSaveOrReplicate(AbstractSaveEventListener.java:288)
at org.hibernate.event.internal.AbstractSaveEventListener.performSave(AbstractSaveEventListener.java:194)
at org.hibernate.event.internal.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:125)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:209)
at org.hibernate.event.internal.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:55)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:194)
at org.hibernate.event.internal.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:49)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:90)
at org.hibernate.internal.SessionImpl.fireSave(SessionImpl.java:715)
at org.hibernate.internal.SessionImpl.save(SessionImpl.java:707)
at org.hibernate.internal.SessionImpl.save(SessionImpl.java:702)
at org.hibernate.test.userTest.main(userTest.java:36)
Caused by: java.sql.SQLException: Field 'pincode' doesn't have a default
value
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1056)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:957)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3376)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3308)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1837)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:1961)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2543)
at
com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1737)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2022)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1940)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1925)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:208)
... 22 more
I had pincode in my address but it was showing an error so i removed it but still it showing that error.
我的地址中有密码，但它显示错误，所以我删除了它，但它仍然显示错误。
Please help me to solve it.
请帮我解决它。
采纳答案by Yellen
The table in your db has a field pincode for which you've not defined a default value and is not nullable. However, your entity has no mapping for that field and you are not sending a value for this field. Thus, java.sql.SQLException: Field 'pincode' doesn't have a default
value
您的数据库中的表有一个字段密码，您尚未为其定义默认值且不可为空。但是，您的实体没有该字段的映射，并且您没有为此字段发送值。因此，java.sql.SQLException: Field 'pincode' 没有默认
值
回答by René Winkler
1) Adapt your entity that it includes the field "pincode"
1) 调整您的实体，使其包含“密码”字段
@Entity
@Table (name="UserDetails")
public class userDetails {
...
@Column(name="pincode", columnDefinition="Number(10) default '34562'")
int pincode;
...
2) or alter the underlying table so that the pincode field has a default value:
2) 或更改基础表，以便 pincode 字段具有默认值：
ALTER TABLE user_details MODIFY pincode NUMBER(10) NULL DEFAULT NULL;
Number(10) is just chosen as an example. Replace this by the variable type of pincode.
仅以 Number(10) 为例。用可变类型的密码替换它。
回答by pooja patil
I had same error as org.hibernate.exception.GenericJDBCException: could not execute statementwhere i forgot to initialize session factory.
我有与org.hibernate.exception.GenericJDBCException相同的错误：无法执行我忘记初始化会话工厂的语句。
Initializing(as follow) session factory resolved my issue.
初始化（如下）会话工厂解决了我的问题。
@Autowired
private SessionFactory sessionFactory;
public void setSessionFactory(SessionFactory sessionFactory) {
this.sessionFactory = sessionFactory;
}
