bash 为目录中的每个文件运行 shell 脚本
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Run shell script for every file in directory
提问by general exception
I have a bunch of files in a directory all named YYYY_MM_DD
我在一个目录中有一堆文件都命名为 YYYY_MM_DD
-rw-r--r-- 1 root root 480K Apr 21 13:17 2012_04_05
-rw-r--r-- 1 root root 483K Apr 21 13:17 2012_04_06
-rw-r--r-- 1 root root 484K Apr 21 13:17 2012_04_07
-rw-r--r-- 1 root root 480K Apr 21 13:17 2012_04_08
-rw-r--r-- 1 root root 344K Apr 21 13:17 2012_04_09
-rw-r--r-- 1 root root 66K Apr 21 13:17 2012_04_10
-rw-r--r-- 1 root root 461K Apr 21 13:17 2012_04_11
-rw-r--r-- 1 root root 475K Apr 21 15:09 2012_04_17
-rw-r--r-- 1 root root 480K Apr 21 15:10 2012_04_18
-rw-r--r-- 1 root root 474K Apr 21 15:10 2012_04_19
-rw-r--r-- 1 root root 474K Apr 21 15:10 2012_04_20
I have a shell script that accepts a file as a paramater and calculates figures based on the data in the file, i call the script like this
我有一个 shell 脚本,它接受一个文件作为参数并根据文件中的数据计算数字,我像这样调用脚本
sh Calculate.sh MyFile
I want to run this shell script for every file in this directory.
我想为这个目录中的每个文件运行这个 shell 脚本。
How would i go about doing this, xargs ??
我将如何去做,xargs ?
采纳答案by MrJames
Have you tried the findcommand with execution ?
您是否尝试过find执行命令?
My sample will echo the files, but you can call a shell script with the filename as a parameter
我的示例将回显文件,但您可以使用文件名作为参数调用 shell 脚本
find . -maxdepth 1 -type f -exec echo {} \;
回答by glenn Hymanman
A simple for loop in the shell:
shell 中的一个简单的 for 循环:
for file in *; do sh Calculate.sh "$file"; done
回答by user unknown
./Calculate.sh 2012_04_{05..20}
回答by Dagang
find . -maxdepth 1 -type f | xargs -n 1 -I % Calculate.sh %
find . -maxdepth 1 -type f | xargs -n 1 -I % Calculate.sh %

