JAVA：在数组中查找值
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JAVA: Finding Values in an Array
提问by Java123
Set numMatches to the number of elements in userValues (having NUM_VALS elements) that equal matchValue. Ex: If matchValue = 2 and userValues = {2, 2, 1, 2}, then numMatches = 3.
将 numMatches 设置为 userValues（具有 NUM_VALS 个元素）中与 matchValue 相等的元素数。例如：如果 matchValue = 2 且 userValues = {2, 2, 1, 2}，则 numMatches = 3。
import java.util.Scanner;
public class FindMatchValue {
public static void main (String [] args) {
final int NUM_VALS = 4;
int[] userValues = new int[NUM_VALS];
int i = 0;
int matchValue = 0;
int numMatches = -99; // Assign numMatches with 0 before your for loop
userValues[0] = 2;
userValues[1] = 2;
userValues[2] = 1;
userValues[3] = 2;
matchValue = 2;
**/* Your solution goes here */**
numMatches = 0;
for(i = 0; i < NUM_VALS; ++i) {
if(userValues[i] == matchValue)
numMatches = i;
}
System.out.println("matchValue: " + matchValue + ", numMatches: " + numMatches);
return;
}
}
My solution has mistakes that I can't figure out.
我的解决方案有我无法弄清楚的错误。
Testing matchValue = 0,
测试 matchValue = 0,
userValues = {0, 0, 0, 0, 0}
用户值 = {0, 0, 0, 0, 0}
Expected value: 5
预期值：5
Your value: 4 <<< This is where I'm going wrong.
您的价值：4 <<< 这是我出错的地方。
回答by Himanshu Bhardwaj
for(i = 0; i < NUM_VALS; ++i) {
if(userValues[i] == matchValue) {
//numMatches = i; //WRONG
numMatches++; //Correct
}
}
This block is incorrect, you are assigning numMatches to the index value of the array rather, it should have been that if there's a match increment values of numMatches by 1.
这个块是不正确的，您将 numMatches 分配给数组的索引值，应该是如果有匹配的 numMatches 增量值 1。
回答by Ajay Pal
numMatches++this is what you need to do in the for loop instead of numMatches = i;
numMatches++这是您需要在 for 循环中执行的操作，而不是 numMatches = i;
