C++ 调试断言失败……_BLOCK_TYPE_IS_VALID(pHead->nBlockUse)

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/8354578/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-28 18:25:16  来源:igfitidea点击:

Debug Assertion Failed … _BLOCK_TYPE_IS_VALID(pHead->nBlockUse)

c++memory-leaksassert

提问by cwin

I have got a really bad memory leak I am trying to fix, but somehow i am not able to delete Objects without triggering this assertation.

我正在尝试修复一个非常糟糕的内存泄漏,但不知何故,我无法在不触发此断言的情况下删除对象。

I have searched for a solution via Google and have read the Questions on stackoverflow about this Error but I was still not able to find the answer!

我已经通过 Google 搜索了解决方案,并阅读了有关此错误的 stackoverflow 上的问题,但我仍然无法找到答案!

Possible reasons to get this Error according to my research:
1. deleting objects more then one
2. shadow copying
3. creating and deleting Objects that are loaded from an external dll
4. creating objects without storing the pointer

根据我的研究,出现此错误的可能原因:
1. 删除多个对象
2. 影子复制
3. 创建和删除从外部 dll 加载的
对象 4. 创建对象而不存储指针

BUT:
1. I checked the code and was not able to find double deletion
2. I use a copy constructor to copy Objects
3. The Error relatet classes are build (with MS Visual Studio) to a seperate lib but not to a dll. AND all the classes that are related to this error are located in the same lib.
4. I checked the code and it seems like that's not the problem

但是:
1. 我检查了代码并且无法找到双重删除
2. 我使用复制构造函数来复制对象
3. 错误相关类构建(使用 MS Visual Studio)到一个单独的库而不是一个 dll。并且与此错误相关的所有类都位于同一个库中。
4.我检查了代码,似乎这不是问题

It would be great if anybody is able to spot the mistake in the code below, and I appreciate every hint that points me to the solution of the problem.

如果有人能够发现下面代码中的错误,那就太好了,我感谢每一个指向我解决问题的提示。

EDIT:
I forgot to mention the same deleting problem in sendThreadMain of MessageSystem (see code below). If i delete the Message there it causes unexpected errors somewhere else in the code. Might just be wrong data transmission... but i do not really know.
This code is run on Windows and Linux!

编辑:
我忘了在 MessageSystem 的 sendThreadMain 中提到同样的删除问题(见下面的代码)。如果我在那里删除消息,它会导致代码中其他地方出现意外错误。可能只是错误的数据传输......但我真的不知道。
此代码可在 Windows 和 Linux 上运行!

Here are the error related parts of the code:

以下是代码中与错误相关的部分:

Message

信息

class Message 
{
public:
    Message (char type, unsigned char id, unsigned short size) 
    {
        mType = type;
        mId = id;
        mSize= size;
    }

    Message(const Message &o)
    {
        mType = o.mType;
        mId = o.mId;
        mSize = o.mSize;
    }

    char getType() const {return mType;};
    unsigned char getId() const {return mId;};
    unsigned short getSize() const {return mSize;};

protected:
    char mType;
    unsigned char mId;
    unsigned short mSize;
};


class JoinMessage : public Message
{
public:
    JoinMessage () : Message ('j', 0, sizeof (JoinMessage))
    {
        team = TEAM_SPECTATOR;
    }
    JoinMessage (unsigned char id) : Message ('j', id, sizeof (JoinMessage)){}
    JoinMessage (const JoinMessage &o) : Message (o)
    {
        team = o.team;
        setName(o.getName());
    }


    void setName(std::string newName)
    {
        if (newName.length() > MAX_PLAYER_NAME_LENGHT)
            newName = newName.substr(0, MAX_PLAYER_NAME_LENGHT);

        memset(name, 0, MAX_PLAYER_NAME_LENGHT);
        for(unsigned int i = 0; i < newName.length(); i++)
            name[i] = newName[i];
    }

    std::string getName() const
    {
        std::string stringToReturn;

        for(unsigned int i = 0; i < MAX_PLAYER_NAME_LENGHT; i++)
        {
            if (name[i])
                stringToReturn.push_back(name[i]);
            else
                break;
        }

        return stringToReturn;
    }

    TeamIdentifier team;

private:
    unsigned char name[MAX_PLAYER_NAME_LENGHT];
};

// there are a lot other messages

MessageQueue

消息队列

MessageQueue::~MessageQueue()
{
    boost::mutex::scoped_lock lock (queueMutex);

    while(messageQueue.size() > 0)
    {
        // the crash is non-reproducible
        // works 90% of the time
        delete messageQueue.front (); // <- Debug Assertion Failed … _BLOCK_TYPE_IS_VALID
        messageQueue.pop_front();
    }

}

void MessageQueue::enqueMessage (Message* message)
{
    {
        boost::mutex::scoped_lock lock (queueMutex);
        messageQueue.push_back(message);
    }
}

Message* MessageQueue::dequeMessage ()
{
    boost::mutex::scoped_lock lock (queueMutex);
    if (messageQueue.size() == 0) 
        return nullptr;

    Message* message = messageQueue.front ();
    messageQueue.pop_front();

    return message;
}

MessageSystem

消息系统

template <class MessageType>
void broadcast (MessageType &message)
{
    MessageType *internMessage = new MessageType(message);

    boost::mutex::scoped_lock lock (mRecipientMapMutex);
    std::map <boost::asio::ip::udp::endpoint, MessageQueue *>::iterator it;

    for (it = mRecipientMap.begin ();
        it != mRecipientMap.end ();
        it++)
    {
        it->second->enqueMessage(internMessage);

    }
}


template <class MessageType>
void post (MessageType &message, boost::asio::ip::udp::endpoint &recipient)
{
    MessageType *internMessage = new MessageType(message);

    std::map <boost::asio::ip::udp::endpoint, MessageQueue* >::iterator it;
    MessageQueue *messageQueue = NULL;
    {
        boost::mutex::scoped_lock lock (mRecipientMapMutex);
        it = mRecipientMap.find (recipient);
        if (it != mRecipientMap.end())
            messageQueue = it->second;

        if(messageQueue)
            messageQueue->enqueMessage (internMessage);
    }

}


void MessageSystem::sendThreadMain ()
{
    // copy endpoints to vecotr so it can be
    // deleted from map while iterating
    std::vector<udp::endpoint> endpoints;
    {
        boost::mutex::scoped_lock lock (mRecipientMapMutex);
        std::map <udp::endpoint, MessageQueue *>::iterator mapIt = mRecipientMap.begin ();
        while (mapIt != mRecipientMap.end())
        {
            endpoints.push_back(mapIt->first);
            mapIt++;
        }
    }

    std::vector<udp::endpoint>::iterator endpointIt = endpoints.begin();
        while (endpointIt != endpoints.end())
        {
            char sendBuffer[PACKET_SIZE];
            int sendBufferPosition = 0;
            {
                boost::mutex::scoped_lock lock (mRecipientMapMutex);

                MessageQueue *messageQueue = mRecipientMap[*endpointIt];
                if (messageQueue == nullptr)
                {
                    mRecipientMap.erase(*endpointIt);
                    endpointIt++;
                    continue;
                }

                while (Message *message = messageQueue->dequeMessage ())
                {
                    if (sendBufferPosition + message->getSize() > PACKET_SIZE) 
                    {
                        // put message back and send it later
                        messageQueue->enqueMessage (message);
                        break;
                    }

                    // copy message into buffer
                    std::memcpy (
                        &sendBuffer [sendBufferPosition], message, message->getSize());

                    sendBufferPosition += message->getSize();
                    // deleting this message causes a crash if 2 or more
                    // recipients are registered within MessageSystem
                    //delete message; <- RANDOM CRASH elsewhere in the program
                }
            }
    .... // more code down here that seems not related to the error

采纳答案by cwin

Today I figured it out on my own. It was #1 of the 4 possibilities mentioned in the Question.

今天我自己弄明白了。它是问题中提到的 4 种可能性中的第 1 种。

  1. deleting objects more then once (by saving multiple pointers to the exact same object)
  1. 多次删除对象(通过保存指向完全相同对象的多个指针)

Here is my Solution in MessageQueue:

这是我在 MessageQueue 中的解决方案:

template <class MessageType>
void broadcast (MessageType &message)
{
    // I was creating 1 new Message right here but I need 1 new Message
    // in EVERY MessageQueue so i moved the next line ...
    // MessageType *internMessage = new MessageType(message);

    boost::mutex::scoped_lock lock (mRecipientMapMutex);
    std::map <boost::asio::ip::udp::endpoint, MessageQueue *>::iterator it;

    for (it = mRecipientMap.begin ();
        it != mRecipientMap.end ();
        it++)
    {
        // ... down here. Now every queue contains its own copy of the Message
        MessageType *internMessage = new MessageType(message);
        it->second->enqueMessage(internMessage);
    }
}

回答by Ahmed U3

Well, I faced similar problem, the following code

好吧,我遇到了类似的问题,以下代码

Message* message = messageQueue.front ();
messageQueue.pop_front();

return message;

The code that produced error with me was:

对我产生错误的代码是:

Point *p = q.LookFor(&q, &pts[5], &Dist);
cout ...
delete p;

It seems that the function delete the pointer it creates in the runtime, so you're not allowed to delete it "again"

该函数似乎删除了它在运行时创建的指针,因此您不能“再次”删除它

so I replaced it with

所以我用

Point p = *(q.LookFor(&q, &pts[5], &Dist));

and it's gone.

它不见了。

回答by Gorpik

It might be a simple problem of wrong order. You are doing:

这可能是一个简单的顺序错误问题。你在做:

while(messageQueue.size() > 0)
{
    delete messageQueue.front();
    messageQueue.pop_front();
}

Maybe deleting the message after popping it, instead of before, would do the trick:

也许在弹出消息后删除消息,而不是之前,可以解决问题:

while(messageQueue.size() > 0)
{
    Message* pFront = messageQueue.front();
    messageQueue.pop_front();
    delete pFront;
}

Anyway, I am not confident at all on this solution, since deleting the object pointed by pFrontshould have no effect on the queue itself, which just stores pointers. But you can try.

无论如何,我对这个解决方案一点信心都没有,因为删除指向的对象pFront应该对队列本身没有影响,队列本身只存储指针。不过你可以试试。