javascript 将选定的选项值从 select 传递给 php
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pass selected option value from select to php
提问by Sanjay Malhotra
<style type="text/css">
form select {
display:none;
}
form select.active {
display:block;
}
</style>
<script type="text/javascript">
window.onload = function () {
var allElem = document.getElementsByName("sl");
for (i = 0; i < allElem.length; i++) {
allElem[i].addEventListener('change', toggleDisplay);
}
}
function toggleDisplay(e) {
var id = 's' + this.value;
var currentSelect = document.getElementsByClassName("active")[0];
if (currentSelect) {
currentSelect.className = "";
}
document.getElementById(id).className = "active";
}
</script>
</head><body>
<form action="check_a.php">
<h2><b>Source: </b></h2>
<input type="radio" name="sl" value="c">Central</input>
<input type="radio" name="sl" value="h">Eastern</input>
<input type="radio" name="sl" value="w">Western</input>
<select id="sc" name="sc">
<option value="1">1</option>
<option value="2">2</option>
</select>
<select id="sh">
<option value="3">3</option>
<option value="4">4</option>
</select>
<select id="sw">
<option value="5">5</option>
<option value="6">6</option>
</select>
<input type="submit" name="submit" value="submit"/>
</form></body></html>
there is one radio button whose value displays the specific select box, which is done using javascript. the value of tag needs to be passed to php code. How can i pass the selected option value to php?
有一个单选按钮，其值显示特定的选择框，这是使用 javascript 完成的。tag 的值需要传递给 php 代码。如何将选定的选项值传递给 php？
回答by Ben
Can't you just set all the selectelements to have the same name?
您不能将所有select元素设置为具有相同的名称吗？
<select id="sc" name="tagvalue">
<option value="1">1</option>
<option value="2">2</option>
</select>
<select id="sh" name='tagvalue'>
<option value="3">3</option>
<option value="4">4</option>
</select>
<select id="sw" name='tagvalue'>
<option value="5">5</option>
<option value="6">6</option>
</select>
Then, just take the value of $_POST['tagvalue'].
然后，只需取 的值$_POST['tagvalue']。
