如何在 Java 中使用 ln
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how to use ln in Java
提问by fang_dejavu
I'm trying to use this formula in JAVA :(-ln(1-L))/L
I'm not sure how to use ln in java.
我试图在 JAVA 中使用这个公式：(-
ln (1-L))/L我不知道如何在 Java 中使用 ln。
采纳答案by Bozho
Math.log(d)returns the natural logarithm (base e) of a double value.
Math.log(d)返回双精度值的自然对数（以 e 为底）。
So the java code will be,
所以java代码将是，
double result = (-Math.log(1-L))/L;
(but note that it's better to have variable names in lower-case - i.e. linstead of L)
（但请注意，最好使用小写的变量名称 - 即l而不是L）
回答by Pops
I also had no idea, but since it's a common math function, I checked the Math classin the API.
我也不知道，但由于它是一个常见的数学函数，我检查了API 中的Math 类。
Here you go: the log method
给你：日志方法
EDIT: Sorry for broken link, Markdown is fixed now. Also I realized right after I posted this answer that it sounds snarky, which was not my intent; re-wordings just make it seems snarky AND sarcastic, though. I just wanted to make the point that the API really is useful for methods that could be reasonably expected to come up a lot.
编辑：抱歉链接断开，Markdown 现在已修复。我也在发布这个答案后立即意识到这听起来很尖刻，这不是我的本意；不过，重新措辞只会让它看起来尖刻和讽刺。我只是想说明这一点，API 对于可以合理预期会出现很多的方法确实很有用。
