C语言 错误：请求成员 ----- 在不是结构或联合的东西中

error: request for member ----- in something not a structure or union

提问by user3306583

I'm trying to access a member of a structure in a function. My struct looks like:

我正在尝试访问函数中结构的成员。我的结构看起来像：

typedef struct {
    int day;
    int month;
    int year;

} date;

The date is input by the user in the main. I am then trying to call the date in the following function:

日期由用户在 main.js 中输入。然后我尝试在以下函数中调用日期：

int is_date_valid(date *dob) {

    printf("year = %d\n", dob.year);
    //Checking if year is a leap year
    if ( dob.year%400 == 0)
        printf("%d is a leap year.\n", dob.year);
    else if ( dob.year%100 == 0)
        printf("%d is not a leap year.\n", dob.year);
    else if ( dob.year%4 == 0 )
        printf("%d is a leap year.\n", dob.year);
    else
        printf("%d is not a leap year.\n", dob.year); 



 return 0;
}

This is giving the error in the title of this post. I understand that I am not accessing the year input into the struct but dont' know how to do this? Would appreciate any help! Thanks

这是这篇文章标题中的错误。我知道我没有访问结构中的年份输入，但不知道该怎么做？将不胜感激任何帮助！谢谢

回答by barak manos

Change dob.yearto dob->year.

更改dob.year为dob->year。

Use .when you have a structure instance.

使用.时，你有一个结构实例。

Use ->when you have a pointer to a structure instance.

->当您有指向结构实例的指针时使用。