Bash 获取命令的返回值并以此值退出
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Bash get return value of a command and exit with this value
提问by RomMer
I want to execute a command then get the return value of this command. when it's done i want to exit and give exit the return value of the previous command, the one i just executed. I already have this piece of code but it doesn't seem to work.
我想执行一个命令然后获取这个命令的返回值。完成后我想退出并给 exit 上一个命令的返回值，我刚刚执行的那个。我已经有了这段代码，但它似乎不起作用。
exec gosu user /var/www/bin/phpunit -c app
typeset ret_code
ret_code=$?
if [ $ret_code == 0 ]; then
exit 0
fi
exit 1
how can i do it ? thanks
我该怎么做 ？谢谢
回答by jschnasse
I think your problem is that typesetitself creates a return value of 0. Try
我认为你的问题是它typeset本身创建了一个 0 的返回值。试试
gosu user /var/www/bin/phpunit -c app
ret_code=$?
return $ret_code
回答by chepner
First of all, execonly returns if it fails, so you'll never see a zero exit status.
首先，exec只有在失败时才返回，因此您永远不会看到零退出状态。
exec gosu user /var/www/bin/phpunit -c app
ret_code=$?
printf 'Error in execing gosu, %d\n' $ret_code
exit $ret_code
Note this error has nothing to do with gosu; if execreturns, it is because the shell was unable to even startgosu, not because gosuitself exited with an error.
请注意，此错误与gosu; 如果exec返回，那是因为 shell 甚至无法启动gosu，而不是因为gosu它本身以错误退出。
Perhaps you didn't mean to use exec, and simply want to run the command and wait for it to complete?
也许您不是有意使用exec，而只是想运行命令并等待它完成？
gosu user /var/www/bin/phpunit -c app
ret_code=$?
if [ $ret_code = 0 ]; then exit 0; fi
printf 'Error in execing gosu, %d\n' $ret_code
exit $ret_code
回答by Christopher Whitehead
Know it has been awhile, but here is more a one liner.
知道已经有一段时间了，但这里有更多的单线。
Something like this...
像这样的东西...
if [ $(gosu user /var/www/bin/phpunit -c app;echo $?) ]; then
exit 0
fi
exit 1
Or even shorter...
或者更短...
return $(gosu user /var/www/bin/phpunit -c app;echo $?)
