不能在类似字节的对象上使用字符串模式 - python 的重新错误
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Can't use a string pattern on a bytes-like object - python's re error
提问by Matchbox2093
I'm doing the python challenge and trying to familiarize myself with python, so without looking at the answers, I tried using python's url reader to read the html and then find the letters needed. However in the code below I get an error, which was originally the python 3 urllib.request but after resolving it I get a new error:
我正在做 python 挑战并试图让自己熟悉 python，所以没有看答案，我尝试使用 python 的 url 阅读器读取 html，然后找到所需的字母。然而，在下面的代码中，我得到一个错误，它最初是 python 3 urllib.request 但在解决它后我得到一个新的错误：
<module> print ("".join(re.findall("[A-Za-z]", data))) File "C:\Python34\lib\re.py", line 210, in findall return _compile(pattern, flags).findall(string) TypeError: can't use a string pattern on a bytes-like object
<module> print ("".join(re.findall("[A-Za-z]", data))) File "C:\Python34\lib\re.py", line 210, in findall return _compile(pattern, flags).findall(string) TypeError: can't use a string pattern on a bytes-like object
Now I tried looking this error up on google, but all I got was about json, which I shouldn't need? My python isn't that strong, so maybe I am doing this incorrectly?
现在我尝试在谷歌上查找这个错误，但我得到的只是关于 json，我不应该需要它？我的蟒蛇不是那么强壮，所以也许我做错了？
#Question 2 - find rare characters
import re
import urllib.request
data = urllib.request.urlopen("http://www.pythonchallenge.com/pc/def/ocr.html")
mess = data.read()
messarr = mess.split("--")
print ("".join(re.findall("[A-Za-z]", data)))
#Question 3 - Find characters in list
page = urllib.request.urlopen("http://www.pythonchallenge.com/pc/def/equality.html")
mess = page.read()
messarr = mess.split("--")
print ("".join(re.findall("[^A-Z]+[A-Z]{3}([a-z])[A-Z]{3}[^A-Z]+", page)))
采纳答案by wouter bolsterlee
The problem is that you're mixing bytes and text strings. You should either decode your data into a text string (unicode), e.g. data.decode('utf-8'), or use a bytes object for the pattern, e.g. re.findall(b"[A-Za-z]")(note the leading bbefore the string literal).
问题是您正在混合字节和文本字符串。您应该将数据解码为文本字符串（unicode），例如data.decode('utf-8')，或使用字节对象作为模式，例如re.findall(b"[A-Za-z]")（注意b字符串文字前的前导）。
