Java 如何使用 Spring RestTemplate 发送 XML POST 请求?

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时间:2020-08-11 16:41:37  来源:igfitidea点击:

How to send XML POST requests with Spring RestTemplate?

javaxmlspring

提问by membersound

Is it possible to send XMLPOSTrequests with spring, eg RestTemplate?

是否可以发送XMLPOST请求spring,例如RestTemplate

I want to send the following xml to the url localhost:8080/xml/availability

我想将以下 xml 发送到 url localhost:8080/xml/availability

<AvailReq>
  <hotelid>123</hotelid>
</AvailReq>

Also do I want to add custom http headers on each request dynamically(!).

我还想在每个请求上动态添加自定义 http 标头吗(!)。

How could I achieve this with spring?

我怎么能用春天实现这一点?

采纳答案by Ali Dehghani

First of all, define your HTTPheaders, like following:

首先,定义您的HTTP标题,如下所示:

HttpHeaders headers = new HttpHeaders();
headers.add("header_name", "header_value");

You can set any HTTPheader with this approach. For well known headers you can use pre-defined methods. For example, in order to set Content-Typeheader:

您可以HTTP使用这种方法设置任何标题。对于众所周知的标头,您可以使用预定义的方法。例如,为了设置Content-Type标题:

headers.setContentType(MediaType.APPLICATION_XML);

Then define a HttpEntityor RequestEntityto prepare your request object:

然后定义一个HttpEntityorRequestEntity来准备你的请求对象:

HttpEntity<String> request = new HttpEntity<String>(body, headers);

If you somehow have access to the XMLstring, you can use HttpEntity<String>. Otherwise you can define a POJO corresponding to that XML. and finally send the request using postFor...methods:

如果您以某种方式可以访问该XML字符串,则可以使用HttpEntity<String>. 否则你可以定义一个对应的 POJO XML。最后使用postFor...方法发送请求:

ResponseEntity<String> response = restTemplate.postForEntity("http://localhost:8080/xml/availability", request, String.class);

Here i'm POSTing the request to the http://localhost:8080/xml/availabilityendpoint and converting the HTTPresponse body into a String.

在这里,我POST将请求发送到http://localhost:8080/xml/availability端点并将HTTP响应正文转换为String.

Note, that in the above examples new HttpEntity<String>(...)can be replaced withnew HttpEntity<>(...)using JDK7 and later.

请注意,在上面的示例中,new HttpEntity<String>(...)可以使用 JDK7 及更高版本替换new HttpEntity<>(...)

回答by Kamill Sokol

Below you find a complete example how to use a RestTemplateto exchange XML documents and receive a HTML response:

下面是一个完整的示例,如何使用 aRestTemplate来交换 XML 文档并接收 HTML 响应:

import static org.hamcrest.Matchers.is;
import static org.junit.Assert.assertThat;
import static org.springframework.test.web.client.match.MockRestRequestMatchers.header;
import static org.springframework.test.web.client.match.MockRestRequestMatchers.content;
import static org.springframework.test.web.client.match.MockRestRequestMatchers.method;
import static org.springframework.test.web.client.match.MockRestRequestMatchers.requestTo;
import static org.springframework.test.web.client.response.MockRestResponseCreators.withSuccess;

import org.junit.Test;
import org.springframework.http.HttpEntity;
import org.springframework.http.HttpHeaders;
import org.springframework.http.HttpMethod;
import org.springframework.http.MediaType;
import org.springframework.http.ResponseEntity;
import org.springframework.test.web.client.MockRestServiceServer;
import org.springframework.web.client.RestTemplate;
import org.w3c.dom.Document;
import org.xml.sax.InputSource;

import java.io.StringReader;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;

public class XmlTest {

    @Test
    public void test() throws Exception {
        RestTemplate restTemplate = new RestTemplate();
        MockRestServiceServer mockServer = MockRestServiceServer.createServer(restTemplate);
        String htmlString = "<p>response</p>";
        String xmlString = "<?xml version=\"1.0\" encoding=\"utf-8\"?><AvailReq><hotelid>123</hotelid></AvailReq>";

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document document = builder.parse(new InputSource(new StringReader(xmlString)));

        mockServer.expect(requestTo("http://localhost:8080/xml/availability"))
                .andExpect(method(HttpMethod.POST))
                .andExpect(content().string(is(xmlString)))
                .andExpect(header("header", "value"))
                .andRespond(withSuccess("<p>response</p>", MediaType.TEXT_HTML));

        HttpHeaders headers = new HttpHeaders();
        headers.add("header", "value");
        HttpEntity<Document> request = new HttpEntity<>(document, headers);

        final ResponseEntity<String> response = restTemplate.postForEntity("http://localhost:8080/xml/availability", request, String.class);

        assertThat(response.getBody(), is(htmlString));
        mockServer.verify();
    }
}

回答by Sam

Find below for example to use a RestTemplate to exchange XML as String and receive a response:

例如,在下面找到使用 RestTemplate 将 XML 交换为 String 并接收响应的示例:

String xmlString = "<?xml version=\"1.0\" encoding=\"utf-8\"?><AvailReq><hotelid>123</hotelid></AvailReq>";

    RestTemplate restTemplate =  new RestTemplate();
    //Create a list for the message converters
    List<HttpMessageConverter<?>> messageConverters = new ArrayList<HttpMessageConverter<?>>();
    //Add the String Message converter
    messageConverters.add(new StringHttpMessageConverter());
    //Add the message converters to the restTemplate
    restTemplate.setMessageConverters(messageConverters);


    HttpHeaders headers = new HttpHeaders();
    headers.setContentType(MediaType.APPLICATION_XML);
    HttpEntity<String> request = new HttpEntity<String>(xmlString, headers);

    final ResponseEntity<String> response = restTemplate.postForEntity("http://localhost:8080/xml/availability", request, String.class);