Python 从 DataFrame 行获取行索引
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Get row index from DataFrame row
提问by orange
Is it possible to get the row number (i.e. "the ordinal position of the index value") of a DataFramerow without adding an extra row that contains the row number (the index can be arbitrary, i.e. even a MultiIndex)?
是否可以在DataFrame不添加包含行号的额外行（索引可以是任意的，即甚至是 MultiIndex）的情况下获取行的行号（即“索引值的序数位置” ）？
>>> import pandas as pd
>>> df = pd.DataFrame({'a': [2, 3, 4, 2, 4, 6]})
>>> result = df[df.a > 3]
>>> result.iloc[0]
a 4
Name: 2, dtype: int64
# but how can I get the original row index of iloc[0] in df?
I could have done df['row_index'] = range(len(df))which would maintain the original row number, but I am wondering if Pandas has a built-in way of doing this.
我本可以df['row_index'] = range(len(df))保持原始行号，但我想知道 Pandas 是否有内置的方法来做到这一点。
采纳答案by EdChum
Access the .nameattribute and use get_loc:
访问.name属性并使用get_loc：
In [10]:
df.index.get_loc(result.iloc[0].name)
Out[10]:
2
