Python 3 定时输入
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Python 3 Timed Input
提问by cloud311
What I would like to be able to do is ask a user a question using input. For example:
我希望能够做的是使用输入向用户提问。例如：
print('some scenario')
prompt = input("You have 10 seconds to choose the correct answer...\n")
and then if the time elapses print something like
然后如果时间过去了，打印出类似的东西
print('Sorry, times up.')
Any help pointing me in the right direction would be greatly appreciated.
任何为我指明正确方向的帮助将不胜感激。
采纳答案by mediocrity
Interesting problem, this seems to work:
有趣的问题，这似乎有效：
import time
from threading import Thread
answer = None
def check():
time.sleep(2)
if answer != None:
return
print "Too Slow"
Thread(target = check).start()
answer = raw_input("Input something: ")
回答by jfs
If it is acceptable to block the main thread when user haven't provided an answer:
如果在用户没有提供答案时阻塞主线程是可以接受的：
from threading import Timer
timeout = 10
t = Timer(timeout, print, ['Sorry, times up'])
t.start()
prompt = "You have %d seconds to choose the correct answer...\n" % timeout
answer = input(prompt)
t.cancel()
Otherwise, you could use @Alex Martelli's answer(modified for Python 3) on Windows (not tested):
否则，您可以在 Windows 上使用@Alex Martelli 的答案（针对 Python 3 进行了修改）（未测试）：
import msvcrt
import time
class TimeoutExpired(Exception):
pass
def input_with_timeout(prompt, timeout, timer=time.monotonic):
sys.stdout.write(prompt)
sys.stdout.flush()
endtime = timer() + timeout
result = []
while timer() < endtime:
if msvcrt.kbhit():
result.append(msvcrt.getwche()) #XXX can it block on multibyte characters?
if result[-1] == '\n': #XXX check what Windows returns here
return ''.join(result[:-1])
time.sleep(0.04) # just to yield to other processes/threads
raise TimeoutExpired
Usage:
用法：
try:
answer = input_with_timeout(prompt, 10)
except TimeoutExpired:
print('Sorry, times up')
else:
print('Got %r' % answer)
On Unix you could try:
在 Unix 上，您可以尝试：
import select
import sys
def input_with_timeout(prompt, timeout):
sys.stdout.write(prompt)
sys.stdout.flush()
ready, _, _ = select.select([sys.stdin], [],[], timeout)
if ready:
return sys.stdin.readline().rstrip('\n') # expect stdin to be line-buffered
raise TimeoutExpired
Or:
或者：
import signal
def alarm_handler(signum, frame):
raise TimeoutExpired
def input_with_timeout(prompt, timeout):
# set signal handler
signal.signal(signal.SIGALRM, alarm_handler)
signal.alarm(timeout) # produce SIGALRM in `timeout` seconds
try:
return input(prompt)
finally:
signal.alarm(0) # cancel alarm
