scala 从字符串中删除多种字符类型
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Removing multiple character types from a string
提问by Hyman
Is this an acceptable approach for removing multiple character types from a string or is there a better (more efficient way)? The "ilr".contains(_)bit feels a little like cheating considering it will be done for each and every character, but then again, maybe this is the right way. Is there a faster or more efficient way to do this?
这是从字符串中删除多个字符类型的可接受方法还是有更好（更有效的方法）？该"ilr".contains(_)位感觉就像作弊考虑它会为每一个字符做了一些，但话又说回来，也许这是正确的方式。有没有更快或更有效的方法来做到这一点？
val sentence = "Twinkle twinkle little star, oh I wander what you are"
val words = sentence.filter(!"ilr".contains(_))
// Result: "Twnke twnke tte sta, oh I wande what you ae"
回答by
I'd just use Java's good old replaceAll(it takes a regexp):
我只是使用 Java 的旧版本replaceAll（它需要一个正则表达式）：
"Twinkle twinkle little star, oh I wander what you are" replaceAll ("[ilr]", "")
// res0: String = Twnke twnke tte sta, oh I wande what you ae
In contrast to working with chars (as in filtering a Seq[Char]), using regular expressions should be Unicode-safe even if you're working with code points outside the basic multilingual plane. "There Ain't No Such Thing As Plain Text."
与使用chars （如过滤 a Seq[Char]）相比，使用正则表达式应该是 Unicode 安全的，即使您使用的是基本多语言平面之外的代码点。“没有纯文本这样的东西。”
回答by om-nom-nom
There would be no significant difference, since there is only 3 characters to remove and no so big string to filter, but you may consider to use Set for this purpose. E.g.
不会有显着差异，因为只有 3 个字符要删除，也没有那么大的字符串要过滤，但您可以考虑使用 Set 来实现此目的。例如
val toRemove = "ilr".toSet
val words = sentence.filterNot(toRemove)
