如何将带引号的参数从变量传递给 bash 脚本
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How to pass quoted arguments from variable to bash script
提问by dcompiled
I tried building a set of arguments in a variable and passing that to a script but the behavior different from what I expected.
我尝试在变量中构建一组参数并将其传递给脚本，但行为与我预期的不同。
test.sh
测试文件
#!/bin/bash
for var in "$@"; do
echo "$var"
done
input
输入
usr@host$ ARGS="-a \"arg one\" -b \"arg two\""
usr@host$ ./test.sh $ARGS
output
输出
-a
"arg
one"
-b
"arg
two"
expected
预期的
-a
arg one
-b
arg two
Note if you pass the quoted arguments directly to the script it works. I also can work around this with eval but I wanted to understand why the first approach failed.
请注意，如果您将带引号的参数直接传递给它可以工作的脚本。我也可以用 eval 解决这个问题，但我想了解为什么第一种方法失败。
workaround
解决方法
ARGS="./test.sh -a "arg one" -b "arg two""
eval $ARGS
回答by chepner
You should use an array, which in some sense provides a 2nd level of quoting:
您应该使用一个数组，它在某种意义上提供了第二级引用：
ARGS=(-a "arg one" -b "arg two")
./test.sh "${ARGS[@]}"
The array expansion produces one word per element of the array, so that the whitespace you quoted when the array was created is not treated as a word separator when constructing the list of arguments that are passed to test.sh.
数组扩展为数组的每个元素生成一个单词，因此在构造传递给 的参数列表时，创建数组时引用的空格不会被视为单词分隔符test.sh。
Note that arrays are not supported by the POSIX shell, but this is the precise shortcoming in the POSIX shell that arrays were introduced to correct.
请注意，POSIX shell 不支持数组，但这是 POSIX shell 中引入数组以纠正的确切缺点。
