如何在C#中获取目录中的文件名
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How to get the name of File in a directory in C#
提问by SyncMaster
Directory.GetFiles(targetDirectory);
Using the above code we get the names(i.e full path)of all the files in the directory. but i need to get only the name of the file and not the path. So how can I get the name of the files alone excluding the path? Or do I need to do the string operations in removing the unwanted part?
使用上面的代码我们得到目录中所有文件的名称（即完整路径）。但我只需要获取文件名而不是路径。那么如何单独获取文件的名称，不包括路径？或者我是否需要执行字符串操作来删除不需要的部分？
EDIT:
编辑：
TreeNode mNode = new TreeNode(ofd.FileName, 2, 2);
Here ofdis a OpenFileDialogand ofd.FileNameis giving the the filename along with it's Path but I need the file name alone.
这ofd是一个OpenFileDialog并ofd.FileName给出了文件名及其路径，但我只需要文件名。
采纳答案by ChrisF
You could use:
你可以使用：
Path.GetFileName(fullPath);
or in your example:
或在您的示例中：
TreeNode mNode = new TreeNode(Path.GetFileName(ofd.FileName), 2, 2);
回答by SO User
Use DirectoryInfo and FileInfo if you want to get only the filenames without doing any manual string editing.
如果您只想获取文件名而不进行任何手动字符串编辑，请使用 DirectoryInfo 和 FileInfo。
DirectoryInfo dir = new DirectoryInfo(dirPath);
foreach (FileInfo file in dir.GetFiles())
Console.WriteLine(file.Name);
回答by Anton
Use:
用：
foreach(FileInfo fi in files)
{
Response.Write("fi.Name");
}
