在初始化/bash 脚本中同时执行多个程序
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Execute several programs at the same time in an initialisation/bash script
提问by Eduardo
Hello I am working with a simulator that uses rcS scripts to boot, this is my script
你好，我正在使用一个使用 rcS 脚本启动的模拟器，这是我的脚本
cd /tests
./test1 &
./test2 &
./test3 &
./test4
exit
What I want is run all the test at the same time and that the exit command is executed only when all the previous test have finished. And not only when test 4 has finished, is this possible?. Thank you.
我想要的是同时运行所有测试，并且只有在所有先前的测试都完成后才会执行 exit 命令。不仅当测试 4 完成时，这可能吗？。谢谢你。
回答by gak
You can use wait:
您可以使用等待：
./test1 &
./test2 &
./test3 &
./test4 &
wait
From the bash man page:
从 bash 手册页：
wait [n ...] Wait for each specified process and return its termination status. Each n may be a process ID or a job specification; if a job spec is given, all processes in that job's pipeline are waited for. If n is not given, all currently active child processes are waited for, and the return status is zero. If n specifies a non-existent process or job, the return status is 127. Otherwise, the return status is the exit status of the last process or job waited for.
wait [n ...] 等待每个指定的进程并返回其终止状态。每个 n 可能是进程 ID 或作业规范；如果给出了作业规范，则等待该作业管道中的所有进程。如果未给出 n，则等待所有当前活动的子进程，返回状态为零。如果 n 指定一个不存在的进程或作业，则返回状态为 127。否则，返回状态为最后等待的进程或作业的退出状态。
回答by firejox
xargscan support parallel
xargs可以支持并行
So just like this:
所以就像这样：
seq 4|xargs -i -n 1 -P 4 ./test{}
回答by Eduardo
Something along the lines of
类似的东西
cd /tests
./test1 &
./test2 &
./test3 &
./test4 &
wait
exit
(I am assuming bash shell)
（我假设 bash shell）
