java 从android的webview访问JSON响应

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时间:2020-11-02 14:16:37  来源:igfitidea点击:

Access the JSON response from webview of android

javaandroidjsonwebview

提问by Chitresh Verma

On Android, I have a webView. I'm loading a urlon it. Firstly, I get a login page of Facebookand after filling login details it gives me a JSON Responseon same webView.

在 Android 上,我有一个webView. 我正在加载url它。首先,我得到一个登录页面,Facebook在填写登录详细信息后,它给了我一个JSON Response相同的webView.

I'm using this code to load that URLbut now I don't know how to get that JSON Responsein a stringwhat I got on finished of that url.

我正在使用此代码来加载它,URL但现在我不知道如何JSON Responsestring我完成的内容中获得它url

WebViewClient yourWebClient = new WebViewClient() {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        return false;
    }

    @Override
    public void onPageFinished(WebView view, String url) {
        wb.loadUrl("javascript:window.HTMLOUT.processHTML('<head>'+document.getElementsByTagName('html')[0].innerHTML+'</head>');");
    }
};
wb = (WebView) findViewById(R.id.webview);
wb.getSettings().setJavaScriptEnabled(true);
wb.getSettings().setSupportZoom(true);
wb.getSettings().setBuiltInZoomControls(true);
wb.setWebViewClient(yourWebClient);
wb.loadUrl("http://pqrs.abcde.com/facebook");

The format of JSON Responseis:

的格式JSON Response是:

{"status":"success","msg":"You have successfully logged in."}

回答by Chitresh Verma

Build a class called MyJavaScriptInterface. And MyJavaScriptInterface to WebView.

构建一个名为 MyJavaScriptInterface 的类。和 MyJavaScriptInterface 到 WebView。

    WebViewClient yourWebClient = new WebViewClient() {

        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            return false;
        }

        @Override
        public void onPageFinished(WebView view, String url) {
            wb.loadUrl("javascript:HtmlViewer.showHTML" +
                    "('<html>'+document.getElementsByTagName('html')[0].innerHTML+'</html>');");
        }
    };
    wb = (WebView) findViewById(R.id.webview);
    wb.getSettings().setJavaScriptEnabled(true);
    wb.getSettings().setSupportZoom(true);
    wb.getSettings().setBuiltInZoomControls(true);
    wb.setWebViewClient(yourWebClient);
    wb.loadUrl("http://pqrs.abcde.com/facebook");
    wb.addJavascriptInterface(new MyJavaScriptInterface(this), "HtmlViewer");


    class MyJavaScriptInterface {

    private Context ctx;
    MyJavaScriptInterface(Context ctx) {
        this.ctx = ctx;      
    }

    @JavascriptInterface
    public void showHTML(String html) {
        System.out.println(html);
    }

}


Note: From you are required to remove window in wb.loadUrl("javascript:...");. And @JavascriptInterface before "public void showHTML".

注意:您需要从 wb.loadUrl("javascript:..."); 中删除窗口。以及“public void showHTML”之前的@JavascriptInterface。

You can get content from showHtml(..) in html parameter.

您可以从 html 参数中的 showHtml(..) 获取内容。

回答by Manju S B

    webView.setWebViewClient(new myWebClient());
    webView.getSettings().setJavaScriptEnabled(true);
    webView.loadUrl(webdata);
}

public class myWebClient extends WebViewClient {
    @Override
    public void onPageStarted(WebView view, String url, Bitmap favicon) {
        // TODO Auto-generated method stub
        super.onPageStarted(view, url, favicon);
    }

    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        // TODO Auto-generated method stub

        view.loadUrl(url);
        return true;

    }
}