如何通过 API 使用 PHP 获取 Instagram 照片？
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How to get instagram photos with PHP by API?
提问by Tanmoy Biswas
Last two days I was trying to display photos from my Instagram profile by raw PHP. But I'm getting these errors.
前两天我试图通过原始 PHP 显示我的 Instagram 个人资料中的照片。但我收到这些错误。
Notice: Trying to get property of non-object in E:\xampp7\htdocs\instagram\index.php on line 29
Warning: Invalid argument supplied for foreach() in E:\xampp7\htdocs\instagram\index.php on line 29
I created proper authenticationfrom instagram API. My requested API clients accessis valid (clientId, userId, accessToken). When I failed with PHP than I tried with a JavaScript Plugin instafeedjs. Now It's working well. Here is my PHP code, given below:-
我从 Instagram API创建了正确的身份验证。我请求的 APIclients access有效 ( clientId, userId, accessToken)。当我使用 PHP 失败时，我尝试使用 JavaScript 插件instafeedjs。现在它运行良好。这是我的 PHP 代码，如下所示：-
<body>
<?php
function fetchData($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 20);
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
$result = fetchData("https://api.instagram.com/v1/users/3550421370/media/recent/?access_token=MY_VALID_ACCESS_TOKEN_IS_HERE");
$result = json_decode($result);
foreach ($result->data as $post) {
if(empty($post->caption->text)) {
// Do Nothing
}
else {
echo '<a class="instagram-unit" target="blank" href="'.$post->link.'">
<img src="'.$post->images->low_resolution->url.'" alt="'.$post->caption->text.'" width="100%" height="auto" />
<div class="instagram-desc">'.htmlentities($post->caption->text).' | '.htmlentities(date("F j, Y, g:i a", $post->caption->created_time)).'</div></a>';
}
}
?>
</body>
回答by Tanmoy Biswas
I get the solution. It is simple by using JSON data as a multi-dimensional array. Every kind of data is able in this array.
我得到了解决方案。使用 JSON 数据作为多维数组很简单。每种数据都可以在这个数组中。
<?php
$access_token = "My_Access_Token";
$photo_count = 9;
$json_link = "https://api.instagram.com/v1/users/self/media/recent/?";
$json_link .="access_token={$access_token}&count={$photo_count}";
$json = file_get_contents($json_link);
$obj = json_decode(preg_replace('/("\w+"):(\d+)/', '\1:"\2"', $json), true);
echo "<pre>";
print_r($obj);
echo "</pre>";
foreach ($obj['data'] as $post){
$pic_text = $post['caption']['text'];
$pic_link = $post['link'];
$pic_like_count = $post['likes']['count'];
$pic_comment_count=$post['comments']['count'];
$pic_src=str_replace("http://", "https://", $post['images']['standard_resolution']['url']);
$pic_created_time=date("F j, Y", $post['caption']['created_time']);
$pic_created_time=date("F j, Y", strtotime($pic_created_time . " +1 days"));
echo "<div class='col-md-4 item_box'>";
echo "<a href='{$pic_link}' target='_blank'>";
echo "<img class='img-responsive photo-thumb' src='{$pic_src}' alt='{$pic_text}'>";
echo "</a>";
echo "<p>";
echo "<p>";
echo "<div style='color:#888;'>";
echo "<a href='{$pic_link}' target='_blank'>{$pic_created_time}</a>";
echo "</div>";
echo "</p>";
echo "<p>{$pic_text}</p>";
echo "</p>";
echo "</div>";
}
?>
回答by Hasan Shahriar
Your API endpoint is wrong. This is the API to fetch recent media of an userfrom Instagram:
您的 API 端点是错误的。这是从 Instagram获取用户最近媒体的 API ：
https://api.instagram.com/v1/users/self/media/recent/?access_token=ACCESS-TOKEN
https://api.instagram.com/v1/users/self/media/recent/?access_token=ACCESS-TOKEN
Get the most recent media published by the owner of the access_token.
获取 access_token 所有者发布的最新媒体。
Parameters
参数
access_tokenA valid access token.
访问令牌A valid access token.
max_idReturn media earlier than this max_id.
最大idReturn media earlier than this max_id.
min_idReturn media later than this min_id.
min_idReturn media later than this min_id.
countCount of media to return.
数数Count of media to return.
Read more: https://www.instagram.com/developer/endpoints/users/#get_users_media_recent_self
阅读更多：https: //www.instagram.com/developer/endpoints/users/#get_users_media_recent_self
