php Laravel 5.5 试图获取非对象的属性“id”
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Laravel 5.5 Trying to get property 'id' of non-object
提问by more
I'm new on Laravel.I used Laravel version 5.5
我是 Laravel 的新手。我使用的是 Laravel 5.5 版
If I try to login with postman.I got "Trying to get property 'id' of non-object" error.And error line is
如果我尝试使用邮递员登录。我收到“试图获取非对象的属性‘id’”错误。错误行是
private $client;
public function __construct(){
$this->client = Client::find(1);
}
public function login(Request $request){
$this->validate($request, [
'username' => 'required',
'password' => 'required'
]);
return $this->issueToken($request, 'password'); // this line has error
}
issueToken Function
issueToken 函数
public function issueToken(Request $request, $grantType, $scope = ""){
$params = [
'grant_type' => $grantType,
'client_id' => $this->client->id,
'client_secret' => $this->client->secret,
'scope' => $scope
];
if($grantType !== 'social'){
$params['username'] = $request->username ?: $request->email;
}
$request->request->add($params);
$proxy = Request::create('oauth/token', 'POST');
return Route::dispatch($proxy);
}
I got same error on Register.But my user successfully registered with 500 error (Trying to get property 'id' of non-object)
我在注册时遇到了同样的错误。但是我的用户成功注册了 500 错误（试图获取非对象的属性“id”）
回答by Sapnesh Naik
The error is because $this->clientis null when find()cannot find the record.
错误是因为找不到记录$this->client时为空find()。
You need to be sure if the record exists or not.
您需要确定该记录是否存在。
Change:
改变：
$this->client = Client::find(1);
To:
到：
$this->client = Client::findOrFail(1);
Documentation:
文档：
From Laravel Eloquent docs,
this will throw a 404error if no record with the specified id is found.
从Laravel Eloquent docs，404如果没有找到具有指定 id 的记录，这将引发错误。
回答by Nimfus
Make sure you have record in database table for User model with id = 1. When you're using User::find(1) Laravel tries to get this record from database, if record is absent this will return null
确保您在数据库表中有 id = 1 的用户模型的记录。当您使用 User::find(1) 时，Laravel 尝试从数据库中获取此记录，如果记录不存在，则返回 null
回答by Sohel0415
In your issueToken()method-
在你的issueToken()方法中——
$client = Client::find(1);
if($client!=null){
$params = [
'grant_type' => $grantType,
'client_id' => $client->id,
'client_secret' => $client->secret,
'scope' => $scope
];
}else{
$params = [
'grant_type' => $grantType,
'client_id' => null,
'client_secret' => null,
'scope' => $scope
];
}
回答by latifa saee
I had the same problem when I was trying access an id which doesn't exist in my project database. This $user= user::findOrFail($id);solved my problem.
当我尝试访问我的项目数据库中不存在的 ID 时，我遇到了同样的问题。这$user= user::findOrFail($id);解决了我的问题。
