bash 使用 netcat 和 grep 有条件地运行命令
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run a command conditionally with netcat and grep
提问by Lectere
I need netcat to listen on incomming HTTP requests, and depending on the request, I need to run a script.
我需要 netcat 来监听传入的 HTTP 请求，并且根据请求，我需要运行一个脚本。
So far I have this;
到目前为止，我有这个；
netcat -lk 12345 | grep "Keep-Alive"
So every time netcat recieves a package that contains a "keep-alive", I need to fire a script.
所以每次 netcat 收到一个包含“keep-alive”的包时，我都需要触发一个脚本。
It needs to run in the crontab...
它需要在 crontab 中运行...
Thanks for your help!
谢谢你的帮助！
回答by wooghie
How about this?
这个怎么样？
#!/bin/bash
netcat -lk -p 12345 | while read line
do
match=$(echo $line | grep -c 'Keep-Alive')
if [ $match -eq 1 ]; then
echo "Here run whatever you want..."
fi
done
Replace the "echo" command with the script you want to execute.
将“echo”命令替换为您要执行的脚本。
回答by anishsane
How about:
怎么样：
#!/bin/bash
netcat -lk -p 12345 | grep 'Keep-Alive' | while read unused; do
echo "Here run whatever you want..."
done
Or
或者
#!/bin/bash
netcat -lk -p 12345 | sed -n '/Keep-Alive/s/.*/found/p' | xargs -n 1 -I {} do_something
# replace do_something by your command.
回答by Burns Fisher
Depending on what you have on the client side, it might sit there waiting for netcat/the server to respond.
根据您在客户端的内容，它可能会坐在那里等待 netcat/服务器响应。
I did a similar thing to the above but used
我做了与上面类似的事情，但使用了
while true do
netcat -l 1234 < 404file.txt
Where 404file.txthas HTTP/1.1 404FILE NOT FOUND
哪里404file.txt有HTTP/1.1 404文件未找到
This disconnects the client and since netcathas no 'k' it terminates and restarts because of the while true, all ready to receive and send the 404 again.
这会断开客户端的连接，并且由于netcat没有“k”，它会因为 while 为真而终止并重新启动，所有准备好再次接收和发送 404。
