bash 将字符串从 Python 返回到 Shell 脚本
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Return string from Python to Shell script
提问by Андрей Далевский
I have Python code like:
我有 Python 代码，如：
x = sys.argv[1]
y = sys.argv[2]
i = sofe_def(x,y)
if i == 0:
print "ERROR"
elif i == 1:
return str(some_var1)
else:
print "OOOps"
num = input("Chose beetwen {0} and {1}".format(some_var2, some_var3))
return str(num)
After I must execute this script in shell script and return string in shell variable, like:
在我必须在 shell 脚本中执行此脚本并在 shell 变量中返回字符串之后，例如：
VAR1="foo"
VAR2="bar"
RES=$(python test.py $VAR1 $VAR2)
Unfortunately it doesn't work. The way by stderr, stdout and stdin also doesn't work due to a lot of print and input() in code. So how I can resolve my issue? Thank you for answer
不幸的是它不起作用。由于代码中的大量打印和输入（），stderr、stdout 和 stdin 的方式也不起作用。那么我该如何解决我的问题呢？谢谢你的答案
回答by chepner
That isn't even valid Python code; you are using returnoutside of a function. You don't wan't returnhere, just a printstatement.
那甚至不是有效的 Python 代码；您在return函数之外使用。你不想return在这里，只是一个print声明。
x, y = sys.argv[1:3]
i = sofe_def(x,y)
if i == 0:
print >>sys.stderr, "ERROR"
elif i == 1:
print str(some_var1)
else:
print >>sys.stderr, "OOOps"
print >>sys.stderr, "Choose between {0} and {1}".format(some_var2, some_var3)
num = raw_input()
print num
(Note some other changes:
（注意其他一些变化：
- Write your error messages to standard error, to avoid them being captured as well.
- Use
raw_input, notinput, in Python 2.
- 将您的错误消息写入标准错误，以避免它们也被捕获。
- 在 Python 2 中使用
raw_input，而不是input。
)
)
Then your shell
然后你的壳
VAR1="foo"
VAR2="bar"
RES=$(python test.py "$VAR1" "$VAR2")
should work. Unless you have a good reason notto, always quote parameter expansions.
应该管用。除非您有充分的理由不这样做，否则请始终引用参数扩展。
回答by volcano
Just use printinstead of return- you bash snippet expects result on STDOUT.
只需使用打印而不是返回- 您的 bash 代码段期望在 STDOUT 上得到结果。
