如何检查文件在 Bash 中是否可执行
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How to check if a file is executable in Bash
提问by demoo
I am trying to build a condition that check if file has execute access bit set. I can't use grep and find.
我正在尝试建立一个条件来检查文件是否设置了执行访问位。我不能使用 grep 和 find。
I tried something with checking the "x" letter in the ls -lcommand but this is wrong in many cases.
我尝试过检查ls -l命令中的“x”字母，但在许多情况下这是错误的。
for val in `ls `
do
if [[ "`ls -l /$val`" -eq *w* ]]
then
rm /$val
fi
done
Please help or give some advices!
请帮忙或给一些建议！
回答by codeforester
There is no need to parse the output of lsto see if a file is executable. Shell provides the built-in -xcheck for that. Using -xfeature, your loop could be re-written as:
无需解析 的输出ls以查看文件是否可执行。Shell 提供了内置的-x检查。使用-x功能，您的循环可以重写为：
for file in ""/*; do
[[ -x "$file" ]] && rm -- "$file"
done
See also:
也可以看看：
回答by iamauser
if [ -x "$file" ]; then
# do something
fi
You can get many more options of file testing using man:
您可以使用以下命令获得更多文件测试选项man：
~]# man test
....
-x FILE
FILE exists and execute (or search) permission is granted
Following should work:
以下应该工作：
~]# find -type f | while IFS='' read -r -d '' p;
do
if [ -x "$p" ]; then
echo "removing $p";
rm "$p";
fi;
done
findcommand gets all the files (including .) in the directory given by $1. whilereads each of these output, if thenchecks individual files for executable permission with-x.
find命令获取.由$1. while读取这些输出中的每一个，if then检查单个文件的可执行权限-x。
EDIT
编辑
After some comments, here is a swifter example:
经过一些评论，这里有一个更快的例子：
find "" -type f -executable -exec rm -- {} \;
