php 如果我只有一个类名字符串，如何从类中调用静态方法？
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How can I call a static method from a class if all I have is a string of the class name?
提问by James Skidmore
How would I get something like this to work?
我怎样才能得到这样的工作？
$class_name = 'ClassPeer';
$class_name::doSomething();
回答by jimyi
Depending on version of PHP:
取决于 PHP 的版本：
call_user_func(array($class_name, 'doSomething'));
call_user_func($class_name .'::doSomething'); // >5.2.3
回答by David Garcia
To unleash the power of IDE autocomplete and error detection, use this:
要释放 IDE 自动完成和错误检测的强大功能，请使用以下命令：
$class_name = 'ClassPeer';
$r = new \ReflectionClass($class_name );
// @param ClassPeer $instance
$instance = $r->newInstanceWithoutConstructor();
//$class_name->doSomething();
$instance->doSomething();
Basically here we are calling the static method on an instance of the class.
基本上，我们在这里调用类的实例上的静态方法。
回答by TJ L
Use call_user_func. Also read up on PHP callbacks.
使用call_user_func. 还阅读了 PHP callbacks。
call_user_func(array($class_name, 'doSomething'), $arguments);
回答by apandit
Reflection (PHP 5 supports it) is how you'd do this. Read that page and you should be able to figure out how to invoke the function like that.
反射（PHP 5 支持它）是您执行此操作的方式。阅读该页面，您应该能够弄清楚如何调用这样的函数。
$func = new ReflectionFunction('somefunction');
$func->invoke();
回答by MaxZoom
After I have almost missed the simplest solution from VolkerK, I have decided to extend and put it in a post. This is how to call the static members on the instance class
在我几乎错过了来自 VolkerK 的最简单的解决方案之后，我决定将其扩展并放在一个帖子中。这是如何调用实例类上的静态成员
// calling class static method
$className = get_class($this);
$result = $className::caluclate($arg1, $arg2);
// using class static member
foreach ($className::$fields as $field) {
:
}
