php json_decode() 期望参数 1 是字符串，给定数组
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json_decode() expects parameter 1 to be string, array given
提问by Jennifer Anthony
What causes this error in my code?
是什么导致我的代码中出现此错误？
$query = $this->db->query("SELECT * FROM tour_foreign ORDER BY id desc");
$data = array();
foreach ($query->result() as $row)
$data[] = array('guide' => $row->guide);
echo json_decode($data); //Line 167
error:
错误：
erro: json_decode() expects parameter 1 to be string, array given: Line Number: 167
UPDATE:
更新：
If I use json_encodeinstead of json_decode, my output is this:
如果我使用json_encode而不是json_decode，我的输出是这样的：
[{"guide":["\u0633\u06cc\u062f \u0633\u0639\u06cc\u062f \u062f\u0627\u062f\u0627\u0634\u0632\u0627\u062f\u0647"]},{"guide":["\u0633\u06c??c\u062f \u0633\u0639\u06cc\u062f \u062f\u0627\u062f\u0627\u0634\u0632\u0627\u062f\u0647"]},{"guide":null}]
They are persian words.
它们是波斯语。
回答by Rocket Hazmat
I think you want json_encode, not json_decode.
我想你想要json_encode，不是json_decode。
回答by Kareem
Set decoding to true
将解码设置为真
Your decoding is not set to true. If you don't have access to set the source to true. The code below will fix it for you.
您的解码未设置为 true。如果您无权将源设置为 true。下面的代码将为您修复它。
$WorkingArray = json_decode(json_encode($data),true);
回答by macintosh264
json_decode() is used to decode a json string to an array/data object. json_encode() creates a json string from an array or data. You are using the wrong function my friend, try json_encode();
json_decode() 用于将 json 字符串解码为数组/数据对象。json_encode() 从数组或数据创建一个 json 字符串。你用错了函数，我的朋友，试试 json_encode();
回答by Akhil Jain
here is the solution for similar problem which i was facing while extracting name from user profile facebook json object
这是我在从用户配置文件 facebook json 对象中提取名称时遇到的类似问题的解决方案
$uname=json_encode($userprof);
$uname=json_decode($uname);
echo "Welcome " . $uname -> name ;
