typescript 如何连接两个不同类型的扩展/继承相同类型的类型化数组？
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How to concat two typed array that are of two different types that extend/inherit the same type?
提问by daniel.sedlacek
I have two classes that inherit from the same superclass:
我有两个继承自同一个超类的类：
class Vehicle {}
class Bus extends Vehicle {}
class Truck extends Vehicle {}
Let's have two typed arrays:
让我们有两个类型化数组：
var buses : Bus[];
var trucks : Truck[];
and a function that accepts an array of the superclass type.
和一个接受超类类型数组的函数。
function checkOil(vehicles : Vehicle[]) {}
I can pass in array of busses or array of trucks but I can not merge them and pass them together:
我可以传递一系列公共汽车或一系列卡车，但我无法合并它们并将它们传递在一起：
function checkOil(buses.concat(trucks));
//error TS2082: Supplied parameters do not match any signature of call target:
Types of property 'pop' of types 'Bus[]' and 'Track[]' are incompatible:
How do I merge those arrays?
我如何合并这些数组？
EDIT: TypeScript Playground
编辑：打字稿游乐场
回答by Radim K?hler
The casting to <Vehicle[]>should work
铸造到<Vehicle[]>应该工作
function checkOil(vehicles : Vehicle[]) {}
checkOil((<Vehicle[]>buses).concat(trucks));
Typescript will cast the (busses)to Vehicle[], and the same will be done with the rest
打字稿将转换为(busses)to Vehicle[]，其余部分也将完成
e.g. this will return (in console) two objects - Vehicles
例如，这将返回（在控制台中）两个对象 - Vehicles
class Vehicle
{
public Type: string;
}
class Bus extends Vehicle
{
public A: string;
}
class Truck extends Vehicle
{
public B: number
}
var buses: Bus[] = [];
buses.push({Type: 'Bus', A : 'A1'});
var trucks: Truck[] = [];
trucks.push({ Type: 'Truck', B: 1 });
function checkOil(vehicles: Vehicle[]) : Vehicle[]
{
return vehicles;
}
var result = checkOil((<Vehicle[]>buses).concat(trucks));
console.log(result)
回答by Ryan Cavanaugh
Just type assert the first array to a common type of the two array types:
只需将第一个数组类型断言为两种数组类型的公共类型：
checkOil((<Vehicle[]>buses).concat(trucks));
