C语言 错误：在此范围内未声明`itoa`
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/6462938/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
error: `itoa` was not declared in this scope
提问by vchitta
I have a sample c file called itoa.cpp as below:
我有一个名为 itoa.cpp 的示例 c 文件，如下所示：
#include <stdio.h>
#include <stdlib.h>
int main ()
{
int i;
char buffer [33];
printf ("Enter a number: ");
scanf ("%d",&i);
itoa (i,buffer,10);
printf ("decimal: %s\n",buffer);
return 0;
}
When i compile the above code with the below command:
当我使用以下命令编译上述代码时：
gcc itoa.cpp -o itoa
i am getting this error:
我收到此错误：
[root@inhyuvelite1 u02]# gcc itoa.cpp -o itoa itoa.cpp: In function "int main()": itoa.cpp:10: error: "itoa" was not declared in this scope
What is wrong in this code? How to get rid of this?
这段代码有什么问题？如何摆脱这种情况？
回答by Mikola
itoa is not ansi C standard and you should probably avoid it. Here are some roll-your-own implementations if you really want to use it anyway:
itoa 不是 ansi C 标准，您应该避免使用它。如果你真的想使用它，这里有一些你自己的实现：
http://www.strudel.org.uk/itoa/
http://www.strudel.org.uk/itoa/
If you need in memory string formatting, a better option is to use snprintf. Working from your example:
如果您需要在内存中格式化字符串，更好的选择是使用 snprintf。从您的示例工作：
#include <stdio.h>
#include <stdlib.h>
int main ()
{
int i;
char buffer [33];
printf ("Enter a number: ");
scanf ("%d",&i);
snprintf(buffer, sizeof(buffer), "%d", i);
printf ("decimal: %s\n",buffer);
return 0;
}
回答by Jexcy
If you are only interested in base 10, 8 or 16. you can use sprintf
如果您只对基数 10、8 或 16 感兴趣，您可以使用 sprintf
sprintf(buf,"%d",i);
回答by meldo
Look into stdlib.h. Maybe _itoa instead itoa was defined there.
查看 stdlib.h。也许 _itoa 而不是 itoa 是在那里定义的。
