PHP：将字符串中的空格转换为 %20？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/5572718/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
PHP: convert spaces in string into %20?
提问by matt
How can I convert spaces in string into %20?
如何将字符串中的空格转换为%20?
Here is my attempt:
这是我的尝试：
$str = "What happens here?";
echo urlencode($str);
The output is "What+happens+here%3F", so the spaces are not represented as %20.
输出为"What+happens+here%3F"，因此空格未表示为%20。
What am I doing wrong?
我究竟做错了什么？
回答by Matthew Flaschen
Use the rawurlencodefunction instead.
请改用该rawurlencode函数。
回答by Alnitak
The plus sign is the historic encoding for a space character in URL parameters, as documented in the helpfor the urlencode()function.
加号是 URL 参数中空格字符的历史编码，如该函数的帮助中所述urlencode()。
That same page contains the answer you need - use rawurlencode()instead to get RFC 3986compatible encoding.
同一页面包含您需要的答案 -rawurlencode()改为使用以获得RFC 3986兼容编码。
回答by David says reinstate Monica
I believe that, if you need to use the %20variant, you could perhaps use rawurlencode().
我相信，如果您需要使用该%20变体，您或许可以使用rawurlencode().
