Linux 如何解决“collect2：ld 返回 1 个退出状态”？
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How to solve 'collect2: ld returned 1 exit status '?
提问by sudha
when I build my source code in linux I got an error like
当我在 linux 中构建我的源代码时，我得到了一个错误
qstring.cpp:(.text+0x2c01): undefined reference to `terminate(void)'
collect2: ld returned 1 exit status
How to solve this problem?
如何解决这个问题呢？
回答by paxdiablo
You need to find out which object file or library terminatelives in and include it in your compile/link command.
您需要找出terminate存在于哪个目标文件或库中，并将其包含在您的编译/链接命令中。
If it's in an object or source file, just give it to your gcc(assuming you're actually usinggcc, if not, the method will probably be similar) command as per normal. If it's in a library, you should look into the -L(library path) and -l(library name) options.
如果它在对象或源文件中，只需按照正常方式将其提供给您的gcc（假设您实际上正在使用gcc，如果没有，该方法可能会类似）命令。如果它在库中，您应该查看-L(library path) 和-l(library name) 选项。
回答by Ben Voigt
void terminate(void) { raise(9); }
void terminate(void) { raise(9); }
回答by Adam Rosenfield
terminateis defined in the C++ standard library, so make sure that you're linking that in. Assuming you're using gcc to compile, you should use the g++executable to compile your source code, notthe gccexecutable:
terminate在C ++标准库的定义，所以请确保您连接，在假设你使用gcc来编译，你应该使用的。g++可执行文件编译源代码，没有的gcc可执行文件：
g++ source.cc -o output
When executed as g++, the linker automatically links in the C++ standard library (libstdc++) for you. If you instead execute gcc as plain gcc, or you directly invoke the linker ld, then you need to add -lstdc++yourself to link in the library, e.g.:
当作为 执行时g++，链接器会自动为您链接 C++ 标准库 (libstdc++)。如果您改为以普通方式执行 gcc gcc，或者您直接调用链接器ld，那么您需要将-lstdc++自己添加到库中的链接，例如：
gcc source.cc -o output -lstdc++ # Compile directly from source
ld source1.o source2.o -o output -lstdc++ # Link together object files
