将 pandas csv 保存到子目录
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/35892452/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Save pandas csv to sub-directory
提问by PaulBarr
I am trying to save the output of the following code to a subdirectory:
我正在尝试将以下代码的输出保存到子目录中：
for gp in g:
filename = gp[0] + '.csv'
print(filename)
gp[1].to_csv(filename)
I have created the subdirectory first:
我首先创建了子目录：
os.makedirs('MonthlyDataSplit')
But I can't find any information as to how to use to_csvto save to a subdirectory rather than the current directory. One approach I was thinking was to use the with "MonthlyDataSplit" open as directorybut I can only find the equivalent for opening a file in a subdirectory.
但是我找不到有关如何使用to_csv保存到子目录而不是当前目录的任何信息。我正在考虑的一种方法是使用 ，with "MonthlyDataSplit" open as directory但我只能找到在子目录中打开文件的等效方法。
采纳答案by EdChum
Basically you can build a path including subdirectories and pass this as the path arg to to_csv:
基本上，您可以构建一个包含子目录的路径并将其作为路径 arg 传递给to_csv：
root = 'MonthlyDataSplit'
for gp in g:
filename = gp[0] + '.csv'
print(filename)
gp[1].to_csv(root + '/' + filename)
You need to add slash separators to indicator what is a directory name and what is a filename, I would propose using os.path.jointo simplify this process:
您需要添加斜杠分隔符来指示什么是目录名和什么是文件名，我建议使用os.path.join来简化这个过程：
In [3]:
import os
root = 'MonthlyDataSplit'
os.path.join(root, 'some_file.csv')
Out[3]:
'MonthlyDataSplit\some_file.csv'
For further subdirectories you can just add a new level:
对于更多的子目录，您可以添加一个新级别：
In [8]:
import os
root = 'MonthlyDataSplit'
day = 'Day'
subdir = os.path.join(root, day)
final_path = os.path.join(subdir, 'some_file_name')
final_path
Out[8]:
'MonthlyDataSplit\Day\some_file_name'
