在针对 WSDL(xsd 架构)验证 xml 时了解 elementFormDefault 限定/不限定

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时间:2020-09-06 14:46:00  来源:igfitidea点击:

Understanding elementFormDefault qualified/unqualified when validating xml against a WSDL (xsd schema)

xmlsoapxsdwsdlxml-namespaces

提问by Felix Schwarz

I'm trying to understand the implications of elementFormDefault="qualified/unqualified"in an XML schema which is embedded in WSDL (SOAP 1.1, WSDL 1).

我试图了解elementFormDefault="qualified/unqualified"嵌入在 WSDL(SOAP 1.1、WSDL 1)中的 XML 模式的含义。

For example I have this schema inside a WSDL:

例如,我在 WSDL 中有这个架构:

<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
    elementFormDefault="qualified"
    targetNamespace="http://www.example.com/library">
    <xsd:element name="person">
        <xsd:complexType>
            <xsd:sequence>
                <xsd:element name="name" type="xsd:string"/>
            </xsd:sequence>
        </xsd:complexType>
    </xsd:element>
</xsd:schema>

In plain XML this is obviously invalid because "name" has no specified namespace:

在纯 XML 中,这显然是无效的,因为“name”没有指定的命名空间:

<lib:person xmlns:lib="http://www.example.com/library">
    <name>XML Schema</name>
</lib:person>

while this is obviously valid because all elements are qualified:

虽然这显然是有效的,因为所有元素都是合格的:

<lib:person xmlns:lib="http://www.example.com/library">
    <lib:name>qualified xml</lib:name>
</lib:person>

But surprisingly libxml says that the following is also valid:

但令人惊讶的是,libxml 表示以下内容也是有效的:

<person xmlns="http://www.example.com/library">
    <name>XML Schema</name>
</person>

Question 1: I assumed that qualifiedmeant <person>should look something like <lib:person xmlns:lib="...">. But the results seem to indicate that the xmlnsattribute does the same?

问题 1:我认为qualifiedmean<person>应该看起来像<lib:person xmlns:lib="...">. 但结果似乎表明该xmlns属性的作用相同?

Now assume that the above XML is part of a SOAP request, e.g.

现在假设上述 XML 是 SOAP 请求的一部分,例如

...
<s:Body>
    <person xmlns="http://www.example.com/library">
        <name>XML Schema</name>
    </person>
</s:Body>
...

Question 2: Is the request above valid if the WSDL contains a qualifiedschema as displayed above? (plain SOAP, disregarding WS-I basic profile)

问题 2:如果 WSDL 包含qualified如上所示的模式,则上述请求是否有效?(普通 SOAP,不考虑 WS-I 基本配置文件)

Question 3When I consider WS-I Basic profile (especially 4.1.13 SOAP Body and Namespaces) is the above request still valid? (is personconsidered "namespace qualified"?)

问题 3当我考虑 WS-I Basic 配置文件(尤其是4.1.13 SOAP Body 和 Namespaces)时,上述请求是否仍然有效?(被person认为是“命名空间合格”?)

回答by Michael Kay

Specifying "qualified" in the schema, which is nearly always the right thing to do, means that local element declarations (xs:element within xs:complexType) refers to elements in the target namespace of the schema. Without it, they refer to elements in no namespace.

在模式中指定“合格”,这几乎总是正确的做法,意味着本地元素声明(xs:complexType 中的 xs:element)引用模式目标命名空间中的元素。没有它,它们将引用没有命名空间的元素。

So with qualified, in your case, the name element must be in the namespace http://www.example.com/library. It will be in this namespace if either

因此,在您的情况下,name 元素必须位于命名空间http://www.example.com/library 中。它将在这个命名空间中,如果

(a) you explicitly put it in this namespace, as in this example:

(a) 你明确地把它放在这个命名空间中,如本例所示:

<lib:person xmlns:lib="http://www.example.com/library">
    <lib:name>qualified xml</lib:name>
</lib:person>

(b) or you use a default namespace, as in this example:

(b) 或者您使用默认命名空间,如本例所示:

<person xmlns="http://www.example.com/library">
    <name>qualified xml</name>
</person>