Python AttributeError: 'Namespace' 对象没有属性
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AttributeError: 'Namespace' object has no attribute
提问by Sam cd
I am writing a program that uses urllib2to download CSV data from an http site. The program works fine when run within Python, however I am also trying to use argparseto be able to enter the url from the command line.
我正在编写一个使用urllib2从 http 站点下载 CSV 数据的程序。该程序在 Python 中运行时运行良好，但是我也尝试使用argparse以便能够从命令行输入 url。
I get the following error when I run it:
运行时出现以下错误：
File "urlcsv.py", line 51, in downloadData
return urllib2.urlopen(url)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 396, in open
protocol = req.get_type()
AttributeError: 'Namespace' object has no attribute 'get_type'
I guess this is part of the urllib2library because it is not code that I have written. Has anybody else encountered similar problems with either the argparseor urllib2modules?
我猜这是urllib2库的一部分，因为它不是我写的代码。有没有其他人遇到过与argparse或urllib2模块类似的问题？
The relevant part of the code is as follows:
代码的相关部分如下：
parser = argparse.ArgumentParser()
parser.add_argument("url")
def main():
"""Runs when the program is opened"""
args = parser.parse_args()
if args is False:
SystemExit
try:
csvData = downloadData(args)
except urllib2.URLError:
print 'Please try a different URL'
raise
else:
LOG_FILENAME = 'errors.log'
logging.basicConfig(filename=LOG_FILENAME,
level=logging.DEBUG,
)
logging.getLogger('assignment2')
personData = processData(csvData)
ID = int(raw_input("Enter a user ID: "))
if ID <= 0:
raise Exception('Program exited, value <= 0')
else:
displayPerson(ID)
main()
def downloadData(url):
return urllib2.urlopen(url)
采纳答案by davidism
You're parsing command line arguments into args, which is a Namespacewith attributes set to the parsed arguments. But you're passing this entire namespace to downloadData, rather than just the url. This namespace is then passed to urlopen, which doesn't know what to do with it. Instead, call downloadData(args.url).
您正在将命令行参数解析为args，这是一个Namespace属性设置为解析参数的属性。但是您将整个命名空间传递给downloadData，而不仅仅是 url。然后将此命名空间传递给urlopen，它不知道如何处理它。相反，调用downloadData(args.url).
回答by Andrii Abramov
Long story short.
长话短说。
Arguments in object returned from parser.parse_args()should be accessed via properties rather than via []syntax.
返回的对象中的参数parser.parse_args()应该通过属性而不是通过[]语法访问。
Wrong
错误的
args = parser.parse_args()
args['method']
Correct
正确的
args = parser.parse_args()
args.method
回答by jjjshade
I had this problem due to a whitespace before the option sting.
由于选项刺痛之前的空格，我遇到了这个问题。
