string 替换字符串中的字符
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Replacing Characters in String
提问by ABANDOND ACOUNT
I am trying to replace all instances of a character in a string of text with another character but I'm not succeeding.
我试图用另一个字符替换文本字符串中一个字符的所有实例，但我没有成功。
Suppose the text is
假设文本是
cat rat mat fat
I want the script to replace all the t's to p's
我希望脚本替换所有 t's to p's
cap rap map fap
What I have is the following but it seems to do little for me.
我所拥有的是以下内容，但它似乎对我没什么用。
SET /P MY_TEXT=ENTER TEXT:
SET T2P=P
SET NEW_TEXT=%TEXT=:T!T2P!%
MSG * %NEW_TEXT%
采纳答案by Grhm
You've got the =sign in the wrong place. Try:
你=在错误的地方找到了标志。尝试：
setlocal enabledelayedexpansion
set /P MY_TEXT=ENTER TEXT:
SET T2P=P
set NEW_TEXT=%MY_TEXT:T=!T2P!%
MSG * %NEW_TEXT%
You can also do the expansion the other way round, i.e.
您也可以反过来进行扩展，即
set NEW_TEXT=!MY_TEXT:T=%T2P%!
回答by Justin
Try this
尝试这个
setlocal
set string=cat rat mat fat
set string=%string:t=p%
回答by Grhm
You could use 'sed' like this:
你可以像这样使用“sed”：
echo "cat rat mat fat" | sed 's/t/p/g' # outputs "cap rap map fap"
