bash 从文件生成频率表
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generating frequency table from file
提问by Javier
Given an input file containing one single number per line, how could I get a count of how many times an item occurred in that file?
给定一个每行包含一个数字的输入文件，我如何计算该文件中某个项目出现的次数？
cat input.txt
1
2
1
3
1
0
desired output (=>[1,3,1,1]):
所需的输出 (=>[1,3,1,1])：
cat output.txt
0 1
1 3
2 1
3 1
It would be great, if the solution could also be extended for floating numbers.
如果解决方案也可以扩展到浮点数，那就太好了。
回答by Caleb
You mean you want a count of how many times an item appears in the input file? First sort it (using -nif the input is always numbers as in your example) then count the unique results.
你的意思是你想要一个项目在输入文件中出现的次数？首先对其进行排序（-n如果输入始终是您的示例中的数字，则使用）然后计算唯一结果。
sort -n input.txt | uniq -c
回答by glenn Hymanman
Another option:
另外一个选项：
awk '{n[]++} END {for (i in n) print i,n[i]}' input.txt | sort -n > output.txt
回答by Mike Sherrill 'Cat Recall'
In addition to the other answers, you can use awk to make a simple graph. (But, again, it's not a histogram.)
除了其他答案之外，您还可以使用 awk 制作一个简单的 graph。（但是，同样，它不是直方图。）
回答by pavium
At least some of that can be done with
至少其中一些可以用
sort output.txt | uniq -c
But the order number countis reversed. This will fix that problem.
但是顺序number count颠倒了。这将解决该问题。
sort test.dat | uniq -c | awk '{print , }'
回答by agc
Using maphimbufrom the Debianstdapackage:
使用maphimbu从Debian的STDA包：
# use 'jot' to generate 100 random numbers between 1 and 5
# and 'maphimbu' to print sorted "histogram":
jot -r 100 1 5 | maphimbu -s 1
Output:
输出：
1 20
2 21
3 20
4 21
5 18
maphimbualso works with floating point:
maphimbu也适用于浮点：
jot -r 100.0 10 15 | numprocess /%10/ | maphimbu -s 1
Output:
输出：
1 21
1.1 17
1.2 14
1.3 18
1.4 11
1.5 19
回答by Chris Koknat
perl -lne '$h{$_}++; END{for $n (sort keys %h) {print "$n\t$h{$n}"}}' input.txt
Loop over each line with -n
Each $_number increments hash %h
Once the ENDof input.txthas been reached,sort {$a <=> $b}the hash numerically
Print the number $nand the frequency $h{$n}
遍历每行-n
的每个$_数目的增量散列%h
一旦END的input.txt已经达到了，sort {$a <=> $b}散列数值
打印的数量$n和频率$h{$n}
Similar code which works on floating point:
适用于浮点的类似代码：
perl -lne '$h{int($_)}++; END{for $n (sort {$a <=> $b} keys %h) {print "$n\t$h{$n}"}}' float.txt
float.txt
浮点数.txt
1.732
2.236
1.442
3.162
1.260
0.707
output:
输出：
0 1
1 3
2 1
3 1
