Java 查找字符串中字符的位置

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时间:2020-08-12 16:00:59  来源:igfitidea点击:

Find Positions of a Character in a String

javastringcharacterindices

提问by Rastin Radvar

How can I find a character in a Stringand print the position of character all over the string? For example, I want to find positions of 'o'in this string : "you are awesome honey"and get the answer = 1 12 17.

如何在 a 中找到一个字符String并在整个字符串中打印字符的位置?例如,我想'o'在这个字符串中找到位置:"you are awesome honey"并得到答案 = 1 12 17

I wrote this, but it doesn't work :

我写了这个,但它不起作用:

public class Pos {
    public static void main(String args[]){
        String string = ("You are awesome honey");
        for (int i = 0 ; i<string.length() ; i++)
        if (string.charAt(i) == 'o')
        System.out.println(string.indexOf(i));
    }
}

采纳答案by Etienne Miret

You were almost right. The issue is your last line. You should print iinstead of string.indexOf(i):

你几乎是对的。问题是你的最后一行。您应该打印i而不是string.indexOf(i)

public class Pos{
    public static void main(String args[]){
        String string = ("You are awesome honey");
        for (int i = 0 ; i<string.length() ; i++)
        if (string.charAt(i) == 'o')
        System.out.println(i);
    }
}

回答by Weyland Yutani

Start from the first character and iterate over all the characters till you reach the end. At each step test whether the character is a 'o'. If it is then print the position.

从第一个字符开始,遍历所有字符直到结束。在每一步测试字符是否是“o”。如果是,则打印位置。

回答by Samuel Petrosyan

    static ArrayList<String> getCharPosition(String str, char mychar) {
            ArrayList<String> positions = new ArrayList<String>();

            if (str.length() == 0)
                return null;

            for (int i = 0; i < str.length(); i ++) {
                if (str.charAt(i) == mychar) {
                    positions.add(String.valueOf(i));
                }
            }

            return positions;
    }

String string = ("You are awesome honey");

ArrayList<String> result = getCharPosition(string, 'o');

for (int i = 0; i < result.size(); i ++) {
    System.out.println("char position is: " + result.get(i));
}

Output:

输出:

char position is: 1
char position is: 12
char position is: 17

回答by Lukas Warsitz

Here in Java:

在 Java 中:

    String s = "you are awesome honey";
    char[] array = s.toCharArray();
    for(int i = 0; i < array.length; i++){
        if(array[i] == 'o'){
            System.out.println(i);
        }   
    }

回答by Phan Van Linh

Here is the function to find all positions of specific character in string

这是查找字符串中特定字符的所有位置的函数

public ArrayList<Integer> findPositions(String string, char character) {
    ArrayList<Integer> positions = new ArrayList<>();
    for (int i = 0; i < string.length(); i++){
        if (string.charAt(i) == character) {
           positions.add(i);
        }
    }
    return positions;
}

And use it by

并使用它

ArrayList<Integer> result = findPositions("You are awesome honey",'o'); 
// result will contains 1,12,17