从 python 列表中删除 'u'
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Remove 'u' from a python list
提问by station
I have a python list of list as follows. I want to flatten it to a single list.
我有一个 python 列表列表如下。我想将其展平为一个列表。
l = [u'[190215]']
I am trying.
我在尝试。
l = [item for value in l for item in value]
It turns the list to [u'[', u'1', u'9', u'0', u'2', u'1', u'5', u']']
它将列表变为 [u'[', u'1', u'9', u'0', u'2', u'1', u'5', u']']
How to remove the ufrom the list.
如何u从列表中删除。
采纳答案by u1860929
In your current code, you are iterating on a string, which represents a list, hence you get the individual characters.
在您当前的代码中，您正在迭代一个表示列表的字符串，因此您将获得单个字符。
>>> from ast import literal_eval
>>> l = [u'[190215]']
>>> l = [item for value in l for item in value]
>>> l
[u'[', u'1', u'9', u'0', u'2', u'1', u'5', u']']
Seems to me, you want to convert the inner string representation of list, to a flattened list, so here you go:
在我看来，您想将列表的内部字符串表示形式转换为扁平列表，因此您可以这样做：
>>> l = [u'[190215]']
>>> l = [item for value in l for item in literal_eval(value)]
>>> l
[190215]
The above will work only when all the inner lists are strings:
以上仅当所有内部列表都是字符串时才有效：
>>> l = [u'[190215]', u'[190216, 190217]']
>>> l = [item for value in l for item in literal_eval(value)]
>>> l
[190215, 190216, 190217]
>>> l = [u'[190215]', u'[190216, 190217]', [12, 12]]
>>> l = [item for value in l for item in literal_eval(value)]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/ast.py", line 80, in literal_eval
return _convert(node_or_string)
File "/usr/lib/python2.7/ast.py", line 79, in _convert
raise ValueError('malformed string')
ValueError: malformed string
回答by jamylak
The umeans a unicodestring which should be perfectly fine to use.
But if you want to convert unicodeto str(which just represents plain bytes in Python 2) then you may encodeit using a character encoding such as utf-8.
这u意味着一个unicode应该完全可以使用的字符串。但是如果你想转换unicode为str（它只代表 Python 2 中的纯字节），那么你可以encode使用诸如utf-8.
>>> items = [u'[190215]']
>>> [item.encode('utf-8') for item in items]
['[190215]']
回答by Kasramvd
You can convert your unicode to normal string with str:
您可以使用以下命令将您的 unicode 转换为普通字符串str：
>>> list(str(l[0]))
['[', '1', '9', '0', '2', '1', '5', ']']
回答by Aneesh R S
use [str(item) for item in list]
用 [str(item) for item in list]
example
例子
>>> li = [u'a', u'b', u'c', u'd']
>>> print li
[u'a', u'b', u'c', u'd']
>>> li_u_removed = [str(i) for i in li]
>>> print li_u_removed
['a', 'b', 'c', 'd']
回答by Kalana
I think this issue occurred in python 2.7but in latest python version udid not displayed when it run
我认为这个问题发生在python 2.7但在最新的 python 版本中你没有在运行时显示
l = [u'[190215]']
l = [item for value in l for item in value]
print(l)
output -:['[', '1', '9', '0', '2', '1', '5', ']']
输出 -：['[', '1', '9', '0', '2', '1', '5', ']']
If you want to concatenatestring items in a list into a single string, you can try this code
如果要将列表中的字符串项连接成单个字符串，可以尝试此代码
l = [u'[190215]']
l = [item for value in l for item in value]
l = ''.join(l)
print(l)
output -:[190215]
输出 -：[190215]
