Linux 如何使用 Bash 读取文件中的倒数第二行?

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时间:2020-08-05 05:38:15  来源:igfitidea点击:

How to read the second-to-last line in a file using Bash?

linuxbashshell

提问by World

I have a file that has the following as the last three lines. I want to retrieve the penultimate line, i.e. 100.000;8438; 06:46:12.

我有一个文件的最后三行如下。我想检索倒数第二行,即100.000;8438; 06:46:12.

.
.
.
99.900; 8423;   06:44:41
100.000;8438;   06:46:12
Number of patterns: 8438

I don't know the line number. How can I retrieve it using a shell script? Thanks in advance for your help.

我不知道行号。如何使用 shell 脚本检索它?在此先感谢您的帮助。

采纳答案by MattH

Try this:

尝试这个:

tail -2 yourfile | head -1

回答by S B

Use this

用这个

tail -2 <filename> | head -1

回答by janc

edand sedcan do it as well.

ed并且sed也可以做到。

str='
99.900; 8423; 06:44:41
100.000;8438; 06:46:12
Number of patterns: 8438
'

printf '%s' "$str" | sed -n -e '${x;1!p;};h'                     # print last line but one
printf '%s\n' H '$-1p' q | ed -s <(printf '%s' "$str")           # same
printf '%s\n' H '$-2,$-1p' q | ed -s <(printf '%s' "$str")       # print last line but two

回答by Dario More Escamez

To clarify what has already been said:

澄清已经说过的内容:

ec2thisandthat | sort -k 5 | grep 2012- | awk '{print }' | tail -2 | head -1

snap-e8317883
snap-9c7227f7
snap-5402553f
snap-3e7b2c55
snap-246b3c4f
snap-546a3d3f
snap-2ad48241
snap-d00150bb

returns

返回

snap-2ad48241

回答by Chen Levy

From: Useful sed one-linersby Eric Pement

来自:Eric Pement 的有用 sed one-liners

# print the next-to-the-last line of a file
sed -e '$!{h;d;}' -e x              # for 1-line files, print blank line
sed -e '1{$q;}' -e '$!{h;d;}' -e x  # for 1-line files, print the line
sed -e '1{$d;}' -e '$!{h;d;}' -e x  # for 1-line files, print nothing

You don't need all of them, just pick one.

您不需要所有这些,只需选择一个即可。

回答by plhn

tac <file> | sed -n '2p'

回答by paranoidduck

A short sed one-liner inspired by https://stackoverflow.com/a/7671772/5287901

https://stackoverflow.com/a/7671772/5287901启发的简短 sed one-liner

sed -n 'x;$p'

Explanation:

解释:

  • -nquiet mode: dont automatically print the pattern space
  • x: exchange the pattern space and the hold space (hold space now store the current line, and pattern space the previous line, if any)
  • $: on the last line, p: print the pattern space (the previous line, which in this case is the penultimate line).
  • -n安静模式:不自动打印模式空间
  • x: 交换模式空间和保持空间(保持空间现在存储当前行,模式空间存储前一行,如果有的话)
  • $: 在最后一行,p: 打印模式空间(前一行,在本例中是倒数第二行)。