Java 在字符串集合中使用通配符搜索
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Search with wildcard in a Collection of String
提问by NEO
I have a HashMap<Integer,String>. I tried the following code to query the Map and return all possible values
我有一个HashMap<Integer,String>. 我尝试了以下代码来查询 Map 并返回所有可能的值
public Collection<String> query(String queryStr) {
List<String> list = new ArrayList<String>();
for (Map.Entry<String, Integer> entry : myMap.entrySet()) {
if (queryStr.matches(entry.getKey()))
list.add(entry.getKey());
}
if (list.isEmpty())
return null;
else
return list;
}
If map has "test","best","crest","zest","testy","tether","temper","teat","tempest". A query of te*tshould return "teat","tempest","test". For 'test*' it should return "test", "testy". How to implement it? Is there any wildcard search for string? And I can't use any external libraries.
如果地图有"test","best","crest","zest","testy","tether","temper","teat","tempest". 的查询te*t应该返回"teat","tempest","test"。对于“test*”，它应该返回“test”、“testy”。如何实施？是否有任何通配符搜索字符串？而且我不能使用任何外部库。
采纳答案by Prabhakaran Ramaswamy
String queryStr="te*t";
queryStr = queryStr.replaceAll("\*", "\\w*");
System.out.println(query(queryStr));
The Complete program
完整的程序
public class sample {
static List<String> values = Arrays.asList("test","best","crest","zest","testy","tether","temper","teat","tempest");
/**
* @param args
*/
public static void main(String[] args) {
String queryStr = "te*t";
queryStr = queryStr.replaceAll("\*", "\\w*");
System.out.println(queryStr);
System.out.println(query(queryStr));
}
public static Collection<String> query(String queryStr) {
List<String> list = new ArrayList<String>();
for (String str : values) {
if (str.matches(queryStr))
list.add(str);
}
if (list.isEmpty())
return null;
else
return list;
}
}
回答by Stefan Finkenzeller
The matcher \w*searches for the following chars only : [a-zA-Z_0-9]
If you would like to search for all the chars using the *matcher then you should try this:
匹配器仅\w*搜索以下字符：[a-zA-Z_0-9]
如果您想使用*匹配器搜索所有字符，则应尝试以下操作：
queryStr = queryStr.replaceAll("\*", ".*");
