在列表中的字符串中查找最后一个单词（Pandas，Python 3）
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Find Last Word in a String within a List (Pandas, Python 3)
提问by user3682157
I have a DF named 'Stories" that looks like this:
我有一个名为“Stories”的 DF，如下所示：
Story
The Man
The Man Child
The Boy of Egypt
The Legend of Zelda
Is there a way to extract the last word in each of those strings?
有没有办法提取每个字符串中的最后一个单词？
Something like:
就像是：
Stories['Prefix'] = final['Story'].str.extract(r'([^ ]*)')
finds the prefix but I am not sure how to adapt it accordingly
找到前缀，但我不确定如何相应地调整它
I was hoping to end up with something like
我希望最终得到类似的东西
Story Suffix
The Word Of Man Man
The Man of Legend Legend
The Boy of Egypt Egypt
The Legend of Zelda Zelda
Any help would be much appreciated!
任何帮助将非常感激！
回答by DSM
You can use .strtwice, as .str[-1]will pick up the last element:
您可以使用.str两次，因为.str[-1]将拾取最后一个元素：
>>> df["Suffix"] = df["Story"].str.split().str[-1]
>>> df
Story Suffix
0 The Man Man
1 The Man Child Child
2 The Boy of Egypt Egypt
3 The Legend of Zelda Zelda
回答by rhaskett
I think split is a little more clear than regex but you can applyany function you choose to a series.
我认为 split 比 regex 更清晰一点，但您可以apply选择一系列的任何函数。
final['Prefix'] = final['Story'].apply(lambda x: x.split()[-1])
回答by EdChum
Use can use a regexp pattern to extract the last word:
使用可以使用正则表达式模式来提取最后一个单词：
In [10]:
df['suffix'] = df.Story.str.extract(r'((\b\w+)[\.?!\s]*$)')[0]
df
Out[10]:
Story suffix
0 The Man Man
1 The Man Child Child
2 The Boy of Egypt Egypt
3 The Legend of Zeldar Zeldar
The pattern is a modified version of the answer I found here: regex match first and last word or any word
该模式是我在此处找到的答案的修改版本：regex match first and last word or any word
回答by A.J. Uppal
To get the last word, you can make a list with each title being an entry in the list, and call this list comprehension to get all the suffixes:
要获得最后一个单词，您可以制作一个列表，其中每个标题都是列表中的一个条目，并调用此列表理解来获取所有后缀：
suffixes = [item.split()[-1] for item in mylist]
This splits the strings by each word, and uses [-1]to get the last entry.
这将按每个单词拆分字符串，并用于[-1]获取最后一个条目。
Then you can write it back whichever way you want.
然后你可以用任何你想要的方式写回它。
The above list comprehension is equivalent to:
上面的列表理解等价于：
suffixes = []
for item in mylist:
suffixes.append(item.split()[-1])) #item.split() to get a list of each word in the string, and [-1] to get the last word
Here is an example:
下面是一个例子：
mylist = ['The Man', 'The Man Child', 'The Boy of Egypt', 'The Legend of Zelda']
suffixes = [item.split()[-1] for item in mylist]
print suffixes #['Man', 'Child', 'Egypt', 'Zelda']
回答by Inox
Not sure if there's any built in function to do it directly. You can iterate through the strings like
不确定是否有任何内置函数可以直接执行此操作。您可以遍历字符串，如
for i in xrange(len(df)):
df['Suffix'].iat[i] = df['Story'].iat[i].split(' ')[len(df['Story'].iat[i].split(' '))-1]
