如何使用java中的正则表达式模式从字符串中提取链接？
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How to extract link from a string using regex patterns in java?
提问by Lokesh
My String:
我的字符串：
download_recording true Package available http://abc.com/recDownload/635131586215948750.exe
download_recording true Package available http://abc.com/recDownload/635131586215948750.exe
How to get http://abc.com/recDownload/635131586215948750.exefrom the above string?
如何http://abc.com/recDownload/635131586215948750.exe从上面的字符串中获取？
please help
请帮忙
回答by tom
Simple use of the split method from the string class should parse this.
简单使用 string 类中的 split 方法应该可以解析这个。
String s = "download_recording true Package available http://abc.com/recDownload/635131586215948750.exe";
//We now have the values on either side of where http:// was
String[] splitted = s.split("http://");
//so index 1 is the url and we can just append http:// back on the beginning to get the whole url
String url = "http://" + splitted[1];
回答by sara
This blog conatins sample code:
此博客包含示例代码：
http://blog.houen.net/java-get-url-from-string/
http://blog.houen.net/java-get-url-from-string/
As well as this question:
以及这个问题：
Detect and extract url from a string?
And this might help as well:
这也可能有帮助：
回答by Hashbrown
This is a very simple one to match things that include a prefixed protocol.
[a-z]+:\/\/[^ \n]*
这是一个非常简单的匹配包含前缀协议的内容。
[a-z]+:\/\/[^ \n]*
Pattern.compile("[a-z]+:\/\/[^ \n]*").matcher(
"download_recording true Package available http://abc.com/recDownload/635131586215948750.exe click the link"
).find();
//"http://abc.com/recDownload/635131586215948750.exe"
Equivalent javascript
等效的 javascript
'download_recording true Package available http://abc.com/recDownload/635131586215948750.exe click the link'
.match(/[a-z]+:\/\/[^ \n]*/)
回答by Aashray
I think this regex is what you are looking for:
我认为这个正则表达式就是你要找的：
(http\:\/\/){0,1}(www){0,1}[\.]{0,1}[a-zA-Z0-9_]+\.[a-zA-Z0-9_]+(\/{1}[a-zA-Z0-9_\.]+)*
(http\:\/\/){0,1}(www){0,1}[\.]{0,1}[a-zA-Z0-9_]+\.[a-zA-Z0-9_]+(\/{1}[a-zA-Z0-9_\.]+)*
