php 将当前日期增加 5 天
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Increase current date by 5 days
提问by Jasper
$date = date('Y-m-d',current_time('timestamp', 0));
How do I change $dateto $date + 5 days?
我如何更改$date为$date + 5 days？
PHP version is 5.2.
PHP 版本是 5.2。
This code doesn't work:
此代码不起作用：
$date_cur = date('Y-m-d',current_time('timestamp', 0));
echo $date_cur . ' <br>';
$date_cur_plus = date($date_cur, strtotime('+5 days'));
echo $date_cur_plus;
Gives me:
给我：
2011-11-29
2011-11-29
回答by matino
$date = date('Y-m-d', strtotime('+5 days'));
回答by Yes Barry
You could use mktime()using the timestamp.
您可以使用mktime()时间戳。
Something like:
就像是：
$date = date('Y-m-d', mktime(0, 0, 0, date('m'), date('d') + 5, date('Y')));
Using strtotime()is faster, but my method still works and is flexible in the event that you need to make lots of modifications. Plus, strtotime()can't handle ambiguous dates.
使用strtotime()速度更快，但我的方法仍然有效，并且在您需要进行大量修改时很灵活。另外，strtotime()无法处理不明确的日期。
Edit
编辑
If you have to add 5 days to an already existing date string in the format YYYY-MM-DD, then you could split it into an array and use those parts with mktime().
如果您必须向格式中现有的日期字符串添加 5 天YYYY-MM-DD，那么您可以将其拆分为一个数组并将这些部分与mktime().
$parts = explode('-', $date);
$datePlusFive = date(
'Y-m-d',
mktime(0, 0, 0, $parts[1], $parts[2] + 5, $parts[0])
// ^ Month ^ Day + 5 ^ Year
);
回答by Turdaliev Nursultan
Object oriented Style:
面向对象风格：
<?php
$date = new DateTime('now');
$date->add(new DateInterval('P5D'));
echo $date->format('Y-m-d') . "\n";
?>
Procedural Style:
程序风格：
<?php
$date = date_create('2016-01-01');
date_add($date, date_interval_create_from_date_string('5 days'));
echo date_format($date, 'Y-m-d');
?>
回答by temuraru
strtotime()is very nice. It allows you to do the following:
strtotime()是非常好的。它允许您执行以下操作：
$startDate = 'now'; // or choose a certain date you want/have
$startDate = '2013-02-14';
$intervals = array(
'',
'+ 5 days',
'+ 31 days',
'+ 3 months',
'+ 2 years + 2 days'
);
foreach($intervals as $interval) {
$combinedDate = $startDate . ' ' . $interval;
var_dump($combinedDate . ' => ' date('Y-m-d', strtotime($combinedDate)));
}
with a result:
结果：
now => 1360334498 = 2013-02-08
now + 5 days => 1360766498 = 2013-02-13
now + 31 days => 1363012898 = 2013-03-11
now + 3 months => 1368020498 = 2013-05-08
now + 2 years + 2 days => 1423579298 = 2015-02-10
现在 => 1360334498 = 2013-02-08
现在 + 5 天 => 1360766498 = 2013-02-13
现在 + 31 天 => 1363012898 = 2013-03-11
现在 + 3 个月 => 1368020498 = 2013-05-08
现在 + 2 年 + 2 天 => 1423579298 = 2015-02-10
or:
或者：
2013-02-14 => 1360792800 = 2013-02-14
2013-02-14 + 5 days => 1361224800 = 2013-02-19
2013-02-14 + 31 days => 1363471200 = 2013-03-17
2013-02-14 + 3 months => 1368478800 = 2013-05-14
2013-02-14 + 2 years + 2 days => 1424037600 = 2015-02-16
2013-02-14 => 1360792800 = 2013-02-14
2013-02-14 + 5 天 => 1361224800 = 2013-02-19
2013-02-14 + 31 天 => 1363471200 = 2013-03-17
2013-02-14 + 3 个月 => 1368478800 = 2013-05-14
2013-02-14 + 2 年 + 2 天 => 1424037600 = 2015-02-16
回答by Francis Avila
$dateplus5 = date('Y-m-d', strtotime('+5 days'));
回答by Taz
You can use
您可以使用
strtotime(“+5 days”)
to get the current date plus 5 days or
获取当前日期加上 5 天或
$targetDate = date($date, strtotime('+5 days'));
回答by Irfan Hafid Nugroho
For specific date:
具体日期：
$date = '2011-11-01';
$date_plus = date('Y-m-d', strtotime($date.'+5 days'));
echo $date.'<br>'.$date_plus;
It will be give :
它将给：
2011-11-01
2011-11-06
回答by bharati bane
I used this:
我用过这个：
$date = strtotime("+1 day", strtotime("2007-02-28"));
echo date("Y-m-d", $date);
It's working now.
它现在正在工作。
回答by Lafif Astahdziq
Did not supposed to be like this?
不应该是这样吗？
$date_cur = date('Y-m-d', current_time('timestamp', 0));
echo $date_cur . ' <br>';
$date_cur_plus = date('Y-m-d', strtotime('+5 days', current_time('timestamp', 0) ) );
echo $date_cur_plus;
