PHP - 如何从时间字符串中获取年、月、日
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PHP - How to get year, month, day from time string
提问by q0987
Given the following timestring:
给定以下时间字符串：
$str = '2000-11-29';
$php_date = getdate( $str );
echo '<pre>';
print_r ($php_date);
echo '</pre>';
How to get the year/month/day in PHP?
如何在 PHP 中获取年/月/日？
[seconds] => 20
[minutes] => 33
[hours] => 18
[mday] => 31
[wday] => 3
[mon] => 12
[year] => 1969
[yday] => 364
[weekday] => Wednesday
[month] => December
[0] => 2000
I don't know why I get 1969 for year.
我不知道为什么我得到 1969 年。
Thank you
谢谢
回答by Daniel Vandersluis
You can use strtotimeto parse a time string, and pass the resulting timestamp to getdate(or use dateto format your time).
您可以使用strtotime来解析时间字符串，并将生成的时间戳传递给getdate（或用于date格式化您的时间）。
$str = '2000-11-29';
if (($timestamp = strtotime($str)) !== false)
{
$php_date = getdate($timestamp);
// or if you want to output a date in year/month/day format:
$date = date("Y/m/d", $timestamp); // see the date manual page for format options
}
else
{
echo 'invalid timestamp!';
}
Note that strtotimewill return falseif the time string is invalid or can't be parsed. When the timestamp you're trying to parse is invalid, you end up with the 1969-12-31 date you encountered before.
请注意，如果时间字符串无效或无法解析，strtotime则会返回false。当您尝试解析的时间戳无效时，您最终会得到之前遇到的 1969-12-31 日期。
回答by Pradeep Bhaskar
PHP - How to get year, month, day from time string
PHP - 如何从时间字符串中获取年、月、日
$dateValue = strtotime($q);
$yr = date("Y", $dateValue) ." ";
$mon = date("m", $dateValue)." ";
$date = date("d", $dateValue);
回答by Raphael Caixeta
Update: Forgot to add semicolon at end of first line, try this:
更新：忘记在第一行末尾添加分号，试试这个：
<?php
$str = "2010-08-29"; // Missed semicolon here
$time = strtotime($str);
// You can now use date() functions with $time, like
$weekday = date("l", $time); // Wednesday or whatever date it is
?>
Hopefully that will get you going!
希望这会让你继续前进！
回答by Typhon
Using the object-oriented programming style, you can do this with DateTime class
使用面向对象的编程风格，您可以使用DateTime 类来做到这一点
$dateFormat = 'Y-m-d';
$stringDate = '2000-11-29';
$date = DateTime::createFromFormat($dateFormat, $stringDate);
Then, you can decompose your date using the format()method
然后，您可以使用format()方法分解您的日期
$year = $date->format('Y'); // returns a string
If you prefer the numeric format, instead of the string format, you can use the intval()function
如果您更喜欢数字格式而不是字符串格式，则可以使用intval()函数
$year = intval($date->format('Y')); // returns an integer
Here some formats that you can use
这里有一些你可以使用的格式
YA full numeric representation of a year, 4 digitsmMonth of the year, 2 digits with leading zerosdDay of the month, 2 digits with leading zerosH24-hour format of an hour, 2 digits with leading zerosiMinutes, 2 digits with leading zerossSeconds, 2 digits with leading zeros
Y一年的全数字表示，4 位数字m一年中的月份，带前导零的 2 位数字d月份中的第几天，带前导零的 2 位数字H小时的 24 小时制，2 位数字，带前导零i分钟，带前导零的 2 位数字s秒，带前导零的 2 位数字
Here the entire list of the formats that you can use : http://php.net/manual/en/function.date.php
这里是您可以使用的格式的完整列表：http: //php.net/manual/en/function.date.php
