bash 我怎么能延迟运行shell脚本
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How could I run a shell script with delay
提问by Jorge Cordero
I basically want to run a script which is a server but with 10 second delay, it is because I need some stuff to run before this script.
我基本上想运行一个服务器脚本，但是有 10 秒的延迟，这是因为我需要在这个脚本之前运行一些东西。
The server is located in the folder /etc/init.dbut basically to make it work I go to that path using the command line and I have to restart the server typing:
服务器位于文件夹中，/etc/init.d但基本上是为了使其工作，我使用命令行转到该路径，我必须重新启动服务器，键入：
sudo ./znodejs.sh stop
And then I start the server again:
然后我再次启动服务器：
sudo ./znodejs.sh start
I would like to know if there is any way to run those commands with a delay.
我想知道是否有任何方法可以延迟运行这些命令。
回答by Has QUIT--Anony-Mousse
The standard unix command for sleeping is called
用于睡眠的标准 unix 命令称为
sleep
to wait a second, use
等一下，使用
sleep 1
回答by Chris Montanaro
In order to make a script run on startup first make it executable:
为了使脚本在启动时运行，首先使其可执行：
$ sudo chmod 755 /etc/init.d/znodejs.sh
Then you can register the script to be run at startup:
然后您可以注册要在启动时运行的脚本：
$ sudo update-rc.d znodejs.sh defaults
(Edit) original answer:
（编辑）原始答案：
the sleep command sill pause for a given number of seconds:
sleep 命令会暂停给定的秒数：
sudo ./znodejs.sh stop
sleep 10
sudo ./znodejs.sh start
