Python 熊猫最大值指数
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Pandas max value index
提问by mGarsteck
I have a Pandas DataFrame with a mix of screen names, tweets, fav's etc. I want find the max value of 'favcount' (which i have already done) and also return the screen name of that 'tweet'
我有一个混合了屏幕名称、推文、收藏夹等的 Pandas DataFrame。我想找到“favcount”（我已经完成）的最大值，并返回该“推文”的屏幕名称
df = pd.DataFrame()
df['timestamp'] = timestamp
df['sn'] = sn
df['text'] = text
df['favcount'] = fav_count
print df
print '------'
print df['favcount'].max()
I cant seem to find anything on this, can anyone help guide me in the right direction?
我似乎无法找到任何关于此的信息，任何人都可以帮助指导我朝着正确的方向前进吗？
回答by Steven G
Use argmax()idxmax()to get the index of the max value. Then you can use loc
使用 来获取最大价值的指标。然后你可以使用argmax()idxmax()loc
df.loc[df['favcount'].idxmax(), 'sn']
Edit:argmax()is now deprecated, switching foridxmax()
编辑：argmax()现在已弃用，切换为idxmax()
回答by jezrael
I think you need idxmax- get index of max value of favcountand then select value in column snby loc:
我认为您需要idxmax- 获取最大值的索引，favcount然后sn通过loc以下方式选择列中的值：
df = pd.DataFrame({'favcount':[1,2,3], 'sn':['a','b','c']})
print (df)
favcount sn
0 1 a
1 2 b
2 3 c
print (df.favcount.idxmax())
2
print (df.loc[df.favcount.idxmax()])
favcount 3
sn c
Name: 2, dtype: object
print (df.loc[df.favcount.idxmax(), 'sn'])
c
