php 传递带空格的字符串变量
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Passing string variable with spaces
提问by rotaercz
In the following code:
在以下代码中：
<script type="text/javascript">
function updateView(set) {
$.post("<?php echo base_url("/show_cards/load_page")."/"; ?>"+set, function( data ) {
$( "#content" ).html( data );
});
}
</script>
'set' is a string variable which can have spaces in it. I'm noticing when it has spaces it's not working correctly. How can I fix this?
'set' 是一个字符串变量，其中可以有空格。我注意到当它有空格时它不能正常工作。我怎样才能解决这个问题？
EDIT: For clarity, I'd like to keep the spaces intact.
编辑：为了清楚起见，我想保持空格完整。
回答by mplungjan
Use $.trim(set)to remove leading or trailing spaces and either
使用$.trim(set)除去开头或结尾的空格，要么
set.replace(/ /g,"+")
or
或者
encodeURI(set)
to keep the spaces inside the string
(refer When are you supposed to use escape instead of encodeURI / encodeURIComponent?)
保留字符串内的空格
（请参阅何时应该使用转义而不是 encodeURI / encodeURIComponent？）
To do both in one go just chain them
一次性完成，只需将它们链接起来
$.trim(set).replace(/ /g,"+")
Note you may use %20 instead of the plus if you prefer.
请注意，如果您愿意，您可以使用 %20 而不是加号。
But is it not a parameter? If so, perhaps you want to pass it as
但它不是一个参数吗？如果是这样，也许您想将其作为
$.post("<?php echo base_url("/show_cards/load_page")."/"; ?>",{"set":$.trim(set).replace(/ /g,"+")},
回答by Rajesh Paul
You have to replace intermediate space(' ') with '%20'with replace()and eliminate boundary spaces(' ') with trim().
您必须' '用'%20'with替换中间空间( ) 并用replace()消除边界空间( ' ') trim()。
So use the following code-
所以使用以下代码 -
<script type="text/javascript">
function updateView(set) {
set=set.trim().replace(/ /g, '%20');
$.post("<?php echo base_url("/show_cards/load_page")."/"; ?>"+set, function( data ) {
$( "#content" ).html( data );
});
}
</script>
回答by Rituraj ratan
use Trim
使用修剪
<script type="text/javascript">
function updateView(set) {
var set=$.trim(set);// by this leading or trailing spaces removes
$.post("<?php echo base_url("/show_cards/load_page")."/"; ?>"+set, function( data ) {
$( "#content" ).html( data );
});
}
</script>
you can also use string.replace
你也可以使用string.replace
var set= set.replace(/ /g,"+") ;// like that way in this all the spaces removes
回答by decongh
Rajesh Paul did a good job with his answer, i don't know why someone gave you a down vote.
Rajesh Paul 的回答做得很好，我不知道为什么有人给你投了反对票。
Good answer Rajesh, it worked for me. This is what i did: '&p_na2=' + (Txtva3).trim().replace(/ /g, '%20');
好的答案 Rajesh，它对我有用。这就是我所做的： '&p_na2=' + (Txtva3).trim().replace(/ /g, '%20');
