pandas 熊猫切片不包括结尾
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Pandas slicing excluding the end
提问by zcadqe
When slicing a dataframe using loc,
使用 loc 对数据帧进行切片时，
df.loc[start:end]
df.loc[开始：结束]
both start and end are included. Is there an easy way to exclude the end when using loc?
包括开始和结束。使用 loc 时是否有一种简单的方法可以排除结尾？
回答by Psidom
locincludes both the start and end, one less ideal work around is to get the index position and use ilocto slice the data frame (assume you don't have duplicated index):
loc包括开始和结束，一个不太理想的解决方法是获取索引位置并用于iloc对数据框进行切片（假设您没有重复的索引）：
df=pd.DataFrame({'A':[1,2,3,4]}, index = ['a','b','c','d'])
df.iloc[df.index.get_loc('a'):df.index.get_loc('c')]
# A
#a 1
#b 2
df.loc['a':'c']
# A
#a 1
#b 2
#c 3
回答by WillZ
Easiest I can think of is df.loc[start:end].iloc[:-1].
我能想到的最简单的就是df.loc[start:end].iloc[:-1].
Chops off the last one.
砍掉最后一个。
